If set A = {1, 2, 3, 4}, how many subsets does A have?

Mathematics

2 answers:

Dmitrij [34]3 years ago

6 0

Answer:

A) 8

Step-by-step explanation:

jasenka [17]3 years ago

3 0

Answer:

I'm pretty sure the answer is A. Sorry if i'm wrong :3

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3 years ago

Which shows the correct simplification of product of powers?

Brums [2.3K]

The power symbols are missing.

I can infere that the product intended to simplify is (7^8) * (7^-4)., because that permits you to use the rule of the product of powers with the same base.

That rule is that the product of two powers with the same base is the base raised to the sum of the powers is:

(A^m) * (A^n) = A^ (m+n)

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4 years ago

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Solve 3x² + 4x = 2. (2 points)

uysha [10]

Answer:

Step-by-step explanation:

As it is a second order equation, it means that it has two possible answers and they are $x_1$ and $x_2$ .

The famous quadratic formula for solving any second order equation is the following:

$x_{1} = \frac{-b + \sqrt{b^2 - 4 ac}}{2a}\\x_{2}=\frac{-b - \sqrt{b^2 - 4 ac}}{2a}$

Where a is the coefficient of $x^2$ , b is the coefficient of x, and c is the free term. In other words,

$a = 3\\b=4\\c=-2$

as the equation should be in the following form:

$a x^2 + bx+c = 0$

Therefore the possible answer should be the following,

$\frac{-4 + \sqrt{4^2 - 4*3*(-2)}}{2*3}=\frac{-4 +\sqrt{16 + 24}}{6} =\frac{-4 + \sqrt{40}}{6}=\\ \frac{-4 + \sqrt{4*10}}{6} = \frac{-4 + 2\sqrt{10}}{6}$ $\frac{2*(-2 + \sqrt{10})}{2*3} = \frac{-2 + \sqrt{10}}{3}$