Step-by-step explanation:
Hey, there!!
Given that,
{ we can write (a^2-4) as (a^2 - 2^2) also as (x^2- 9) can be written as (x^2 - 3^2)}.
We have a^2-b^2= (a+b) (a-b), so keep same formula on it.
(x+3) in numerator and denominator gets cancelled,
Therefore, (x-3) is the final value.
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
A straight line needs two pieces of information to be identified, a gradient and a y-intercept (technically any point will do but the y-intercept is particularly convenient if we have it).
The gradient is calculated by taking two points on the line, and dividing the change in y-coordinate by the change in x-coordinate between them. I'm going to take the points (0,-3) and (2,-2).
The change in y-coordinate is (-2) - (-3) = 1
The change in x-coordinate is (2) - (0) = 2.
Gradient = m = 1/2
Next we identify the y-intercept, the value of y when x = 0. This value is -3, and we call it c.
The equation of a line in slope-intercept form is y = mx + c. Slotting in the values for m and c we have ascertained, we find that the equation of this line is:
y = (1/2)x - 3
I hope this helps :)
C = 4
Use the formula a^2 + b^2 = c^2
5 = a and 4 = b
Answer:
KL=2
Step-by-step explanation:
JK+KL=JL
3x+x+1=5
4x=5-1
4x=4
x=1
KL=x+1
KL=2
