Answer:
4 weekdays and 2 weekends.
Step-by-step explanation:
6 days.
x = weekdays
y = weekends
7x = amount with weekdays
12y = amount with weekends
7x + 12y = 52, total
x + y = 6, amount of days
solve double variable equation
x = 6 - y, plug in to 1st equation
7(6 - y) + 12y = 52
42 - 7y + 12y = 52
5y = 10
y = 2 weekends
2 + x = 6
x = 4 weekdays
Answer:
If it opens at 5:30, then it closes at 10:00 AM
If it opens at 6, then it closes at 10:30 AM
If it opens at 6:30, then it closes at 11:00 AM
If it opens at 7, then it closes at 11:30 AM
If it opens at 7:30, then it closes at 12:00 PM
After 12:00 PM, no one is going to have breakfast. So these are the only possibilities of the timing it will open. Either at 5:30, 6, 6:30, 7, or 7:30.
Hi!
For this equation, you can solve it by using the quadratic formula:
x=-b<span>±sqrt/b^2-4ab
-----------------------
2a</span>
The zeroes for the given polynomial will be 1 and 3.
<h3>What is a polynomial?</h3>
Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.
![\rm a_1x+a_2x^2+a_3x^3+a_4x^4..........a_nx^n](https://tex.z-dn.net/?f=%5Crm%20a_1x%2Ba_2x%5E2%2Ba_3x%5E3%2Ba_4x%5E4..........a_nx%5En)
It is given that the polynomial is, p(x)=2x⁴-8x³+6
![=2x^4-8x^3+6 \\\\ =2\left(x^4-4x^3+3\right) \\\\ =2\left(x-1\right)\left(x^3-3x^2-3x-3\right) \\\\ 2(x-1)+x^2(x-3)-3(x-3) \\\\ x =1 \\\\ x = 3](https://tex.z-dn.net/?f=%3D2x%5E4-8x%5E3%2B6%20%5C%5C%5C%5C%20%3D2%5Cleft%28x%5E4-4x%5E3%2B3%5Cright%29%20%5C%5C%5C%5C%20%3D2%5Cleft%28x-1%5Cright%29%5Cleft%28x%5E3-3x%5E2-3x-3%5Cright%29%20%5C%5C%5C%5C%202%28x-1%29%2Bx%5E2%28x-3%29-3%28x-3%29%20%5C%5C%5C%5C%20x%20%3D1%20%5C%5C%5C%5C%20x%20%3D%203)
Thus, the zeroes for the given polynomial will be 1 and 3.
The question is incomplete the complete question is"Consider the polynomial p(x)=2x⁴-8x³+6
a. Graph p(x)=2x⁴-8x³+6, and find the real zero of polynomial p.
Learn more about Polynomial here:
brainly.com/question/17822016
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Answer:
The side opposite the right angle is the hypotenuse. The Pythagorean theorem is used to solve for the length of the hypotenuse. If a right triangle has legs measuring a and b with hypotenuse c, the Pythagorean theorem is a² + b² = c². Solving for c is as simple as taking the square root of both sides of the equation.