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kompoz [17]
3 years ago
12

What do you look for to help determine y-intercept?

Mathematics
1 answer:
harina [27]3 years ago
6 0
You look to see which point crosses the y-axis. This point will always have an c coordinate of 0.
You might be interested in
The length of the base of a rectangular prism is 9
Tatiana [17]

Answer:

The volume of the prism is <u>320 15/16 inches³</u>.

Step-by-step explanation:

Given:

The length of the base of a rectangular prism is 9 7/8.

The width of the prism is 8 1/8.

And the height is 4 inches.

Now, to find the volume of the prism.

(Length) <em> l = 9 7/8 = 79/8 inches.</em>

(Width)  <em> w = 8 1/8 = 65/8 inches</em>.

(Height)  <em>h = 4 inches</em>.

So, by putting the formula to get the volume:

Volume = w×h×l.

Volume=\frac{65}{8}\times 4\times \frac{79}{8}

Volume=320\frac{15}{16}

<em>Volume = 320 15/16 inches³.</em>

Therefore, the volume of the prism is 320 15/16 inches³.

7 0
3 years ago
Write the equation of a line that is perpendicular to the given line and that passes through the given point.
poizon [28]

Answer: y=-3x+29

Step-by-step explanation:

First put in y-intercept form to find the slope

4x-12y=2\\-12y=-4x+2\\y=\frac{1}{3} x-\frac{1}{6}

Slope of the 1st equation is 1/3-  the slope of the line perpendicular is the opposite reciprocal, so in the case it is -3

Use the point and the new slope to write the new equation in point slope format

y-y_{1} =m(x-x_{1} )\\y-(-1)=-3(x-10)\\y+1=-3x+30\\y=-3x+29

8 0
3 years ago
If AB,BC, and AC are 7 inches, 9 inches, and 10 inches, respectively, and XY is 9 inches, find XZ
Ket [755]

Answer:

d) 12.9 in

Step-by-step explanation:

3)

ΔABC ≅ ΔXYZ

AB/AC = XY/XZ

7/10 = 9/XZ

XZ = 10 *9/7  

XZ = 12.9

Answer:

d) 12.9 in

5 0
3 years ago
S
Korolek [52]

Answer:

D

Step-by-step explanation:

If its right let me know I think this is right

8 0
3 years ago
find the equation of the sides of an isosceles right angled triangle whose vertex is (-2,-3) and the base is on the line x=0​
Serggg [28]

Answer:

AC:y=x-1  CB:y=-x-5 AB:x=0

Step-by-step explanation:

Consider the triangle. The base AB is on the line x=0, the vertex C is (-2,-3)

The side AC is equal to BC. The angle ACB is 90 degrees. If the base is on the line x=o, it is on the axis Y.Explore the distance from the point C to the AB

c(-2,-3), the distance to the axis Y is equal to the modul of the coordinate x (-2), it is 2. The coordinates of point projected by the point C to the axis Y is N(0,-3). The modul of the height is 2, the height of the isosceles triangle to the base is the bisectrix, so the angle BCA is 90/2=45degrees, CBA is 180-90-45=45 degrees too

the heigt CN is equal to side NB, NB=2

Suppose B is (0,y) (x=0 because the base is on this line)

THe modul of the vector NB is equal to sqrt ((0-0)^2+(y+3)^2)= 2

modul (y+3)= 2

y=-1 or y=-5

(0,-1), (0,-5) - two points, one of them (suppose B) is (0,-5) when A is (0,-1) (A is remote from the point N on the same distance with B, because AB is the median too)

Find CB and AC

Use the equation for AC

(x-0)/(-2-0)= (y+1)/(-3+1)

x/-2= (y+1)/-2

x=y+1

y=x-1

For CB

(x-0)/ (-2-0)= (y+5)/ (-3-(-5))

x/-2= (y+5)/2

-x=y+5

y=-x-5

7 0
2 years ago
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