For this case, the first thing we must do is define a variable.
We have then:
x: unknown number
We now write the equation that models the problem:
![(\frac{1}{2}) x + 15 = 9](https://tex.z-dn.net/?f=%20%28%5Cfrac%7B1%7D%7B2%7D%29%20x%20%2B%2015%20%3D%209%20%20%20)
From here, we clear the value of x.
We multiply both sides of the equation by 2:
![(\frac{2}{2}) x + 2 (15) = 2 (9)\\x + 30 = 18](https://tex.z-dn.net/?f=%20%28%5Cfrac%7B2%7D%7B2%7D%29%20x%20%2B%202%20%2815%29%20%3D%202%20%289%29%5C%5Cx%20%2B%2030%20%3D%2018%20%20%20)
We subtract 30 on both sides of the equation:
![x + 30 - 30 = 18 - 30\\x = -12](https://tex.z-dn.net/?f=%20x%20%2B%2030%20-%2030%20%3D%2018%20-%2030%5C%5Cx%20%3D%20-12%20%20)
Answer:
The value of the unknown number is given by:
![x = -12](https://tex.z-dn.net/?f=%20x%20%3D%20-12%20)
The answer to your question is D. 512
Answer: 14 / 20 = 70%
Step-by-step explanation:
Do you have a picture or something?
Answer:
Step-by-step explanation:
The foci are horizontally aligned.
horizontal ellipse:
(x-h)²/a² + (y-k)²/b² = 1
center (h,k)
vertices (h±a,k)
length of minor axis = 2b
foci (h±c,k), c² = a²-b²
Apply your data and solve for h, k, a, and b.
foci (±3√19, 6)
h = 0
k = 6
Length of minor axis = 2b = 10
b = 5
foci (h±3√19, 6)
c = 3√19
c³ = a² - b²
171 = a² - 25
a² = 196
x²/196 + (y-6)²/25 = 1