I hope the choices for the numerators of the solutions are given.
I am showing the complete work to find the solutions of this equation , it will help you to find an answer of your question based on this solution.
The standard form of a quadratic equation is :
ax² + bx + c = 0
And the quadratic formula is:
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
So, first step is to compare the given equation with the above equation to get the value of a, b and c.
So, a = 10, b = -19 and c = 6.
Next step is to plug in these values in the above formula. Therefore,
So,
So,
Hope this helps you!
Answer:
First number=6
Second number=14
Step-by-step explanation:
Let the first number be x
So the second number is x+8
So the sum of the two is
X+x+8=20
2x+8=20
2x=20-8
2x=12
X=12/2
=6
The second number will x+8
So 6+8=14
First number=6
Second number=14
The equation factored would be (x+7)(x-2). As 7-2=5 and (7)(2)=14.
A. 2
b. 0
c. -2
d. 0
f(x) just means that the number in the parentheses is the x-value and if it asks for f(x) it wants the y-value at that x point
Positive and a positive, will always be a positive because theyre both the same. If two things are the same, theyre equal. ( this is from what ik,I read it as a common sense question)
