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3 years ago

I need help ASAP will mark the brainliest

Mathematics

1 answer:

IgorLugansk [536]3 years ago

7 0

Answer:

addition property

Step-by-step explanation:

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Evaluate and simplify the following complex fraction. 2/3÷4/-9 please help me

mariarad [96]

Answer: -3/2

Step-by-step explanation:

−9

−4

−3

7 0

3 years ago

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Jan rode to her friend's house with a constant speed of 14 m/hr. How long will she take to

sammy [17]

Answer:

1.07 hours

Step-by-step explanation:

14 miles = 1 hour

15 miles = x hours

Equal these two together

14 mi/1hr = 15 mi/xhr

Cross multiply

14 mi × x hr = 1 hr × 15 mi

I will stop using the units for now so it won't be as confusing

14x = 15

Divide both sides by 14 to isolate the variable

14x ÷ 14 = 15 ÷ 14

x = 1.07... hours

4 0

3 years ago

What to the tenth power can get you 300

OLEGan [10]

Answer:

1.7689 (rounded to 4 decimal places)

Step-by-step explanation:

Let the number we are seeking be "x", thus we can write the equation as:

$x^{10}=300$

Since we have raised "x" to the "10th power", to get "x" back again, we need to take 10th root. Same goes for right side, we take 10th root of 300. We will get our answer. The process shown below:

$x^{10}=300\\\sqrt[10]{x^{10}} =\sqrt[10]{300} \\x=\sqrt[10]{300} \\x=1.7689$

hence, 1.7689 raised to 10th power will give us 300

5 0

3 years ago

Use the properties of limits to help decide whether the limit exists. If the limit exists, find its value. ModifyingBelow lim W

Sergeu [11.5K]

Answer:

The value of given limit problem is 0.

Step-by-step explanation:

The given limit problem is

$lim_{x\rightarrow \infty}\dfrac{6x^3+5x-7}{6x^4-4x^3-9}$

We need to find the value of given limit problem.

Divide the numerator and denominator by the leading term of the denominator, i.e., $x^4$

$lim_{x\rightarrow \infty}\dfrac{\frac{6x^3+5x-7}{x^4}}{\frac{6x^4-4x^3-9}{x^4}}$

$lim_{x\rightarrow \infty}\dfrac{\frac{6}{x}+\frac{5}{x^3}-\frac{7}{x^4}}{6-\frac{4}{x}-\frac{9}{x^4}}$

Apply limit.

$\dfrac{\frac{6}{ \infty}+\frac{5}{ \infty}-\frac{7}{ \infty}}{6-\frac{4}{ \infty}-\frac{9}{ \infty}}$

We know that $\frac{1}{\infty}=0$ .

$\dfrac{0+0-0}{6-0-0}$

$\dfrac{0}{6}$

$0$

Hence, the value of given limit is 0.

8 0

3 years ago

SOMEBODY HELP ME ILL GIVE BRAINLIEST, NO LINKS!

Sedbober [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

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