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2 years ago

HELPP!!

Mathematics

1 answer:

Tamiku [17]2 years ago

4 0

Answer:

$1,562.50

Step-by-step explanation:

Markup= (selling price- cost)/cost

Let cost be represented by C

0.20 = (1875-C)/ C

0.20C = 1875 - C

0.20C+ C = 1875

1.20C=1875

Divide both sides by 1.20;

C= 1875/1.20

C= $1,562.50

The wholesale cost was $1,562.50

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The graph shows the solution to a system of inequalities:

tangare [24]

Answer:

Option A. $4x+3y\leq 12$ and $x\geq 0$

Step-by-step explanation:

we know that

The solution of the first inequality is the shaded area below the solid line $4x+3y=12$

The solid line passes through the points (0,4) and (3,0) (the y and x intercepts)

therefore

The first inequality is

$4x+3y\leq 12$

The solution of the second inequality is the shaded area to the right of the solid line x=0

therefore

The second inequality is

$x\geq 0$

7 0

2 years ago

During a flu epidemic, 35% of the school's students have the flu. Of those with the flu, 90% have high

frutty [35]

Answer: 0.8015

Step-by-step explanation:

Let F= event that a person has flu

H= event that person has a high temperature.

As per given,

P(F) =0.35

Then P(F')= 1- 0.35= 0.65 [Total probability= 1]

P(H | F) = 0.90

P(H|F') = 0.12

By Bayes theorem, we have

$P(F|H)=\dfrac{P(F)\timesP(H|F)}{P(F)\timesP(H|F)+P(F')\timesP(H|F')}\\\\=\dfrac{0.35\times0.90}{0.35\times0.90+0.65\times0.12}\\\\=\dfrac{0.315}{0.315+0.078}\approx0.8015$

Required probability = 0.8015

8 0

3 years ago

PLEASE HELP FAST!!!

Leni [432]

Answer:

Hello,

I just think that it is A

Why you may ask?

Because it has a Zero and that is an undefined number than

Step-by-step explanation:

Please I want brainest

6 0

2 years ago

Help ........................................................

lakkis [162]

The correct answer is D
Hope this helped :)

3 0

3 years ago

Express the quotient of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5C

Lesechka [4]

Answer:

Solution : $-\frac{3}{4}-\frac{3}{4}i$

Step-by-step explanation:

$-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]$

Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

$\frac{-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)}{2\sqrt{2}\left(0-1\right)i}$