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Tema [17]
3 years ago
14

Simplify the expression below. Make sure to reduce all fractions. 8sec(x)/-7sec(x)

Mathematics
1 answer:
Sidana [21]3 years ago
7 0

Answer:

- \frac{8}{7}

Step-by-step explanation:

Given

\frac{8secx}{-7secx} ← cancel sec x on numerator/ denominator

= \frac{8}{-7}

= - \frac{8}{7}

You might be interested in
SOLUTION We observe that f '(x) = -1 / (1 + x2) and find the required series by integrating the power series for -1 / (1 + x2).
Ann [662]

Answer:

Required series is:

\int{\frac{-1}{1+x^{2}} \, dx =-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....

Step-by-step explanation:

Given that

                           f'(x) = -\frac{1}{1 + x^{2}} ---(1)

We know that:

                  \frac{d}{dx}(tan^{-1}x)=\frac{1}{1+x^{2}} ---(2)

Comparing (1) and (2)

                           f'(x)=-(tan^{-1}x) ---- (3)

Using power series expansion for tan^{-1}x

f'(x)=-tan^{-1}x=-\int {\frac{1}{1+x^{2}} \, dx

= -\int{ \sum\limits^{ \infty}_{n=0} (-1)^{n}x^{2n}} \, dx

= -\sum{ \int\limits^{ \infty}_{n=0} (-1)^{n}x^{2n}} \, dx

=-[c+\sum\limits^{ \infty}_{n=0} (-1)^{n}\frac{x^{2n+1}}{2n+1}]

=C+\sum\limits^{ \infty}_{n=0} (-1)^{n+1}\frac{x^{2n+1}}{2n+1}

=C-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....

as

                 tan^{-1}(0)=0 \implies C=0

Hence,

\int{\frac{-1}{1+x^{2}} \, dx =-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....

7 0
3 years ago
What is the length of the paper clip to the nearest inch?
NARA [144]

The paper clip's length, as shown in the picture, is closest to C. 2 inches.

I hope this helps :)

4 0
3 years ago
What type of angles are ∠4 and∠6? Question 2 options: adjacent angles alternate exterior angles alternate interior angles corres
lianna [129]

Angles 4 and 6 are called Alternate Exterior Angles

Step-by-step explanation:

Alternate Exterior Angles are a pair of angles on the outer side of the each of two lines but on opposite sides of the transversal.

When we take two parallel lines they will create 8 angles, such as 1,2,3,4,5,6,7 & 8.

In that angle 6 is 65 degrees.

Angles 1,2,3 & $ are in one line and remaining four angles on other line.

So Angles 4 and 6 are alternate exterior angles.

5 0
3 years ago
Need Help, thanks:)<br><br> Please help
just olya [345]
It's answer c for sure
4 0
3 years ago
Read 2 more answers
B2 - 7b + 12 = 0
olga_2 [115]
B2-7b+12=0
(b-3)(b-4)=0
b= 3 or 4
6 0
3 years ago
Read 2 more answers
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