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boyakko [2]
3 years ago
5

Hey there i posted picture of question can you help please

Mathematics
1 answer:
Alexeev081 [22]3 years ago
8 0
1. To solve this problem you must apply the proccedure shown below:

2. When you multiply two polynomials, you must apply the distributive property and multiply the coefficients and add the exponents. For example:

 (x)(x^2)

 The coefficients of both terms are 1 and the sum of the exponents is 3= (1+2=3)

 Therefore:

  (x)(x^2)=x^3

 3. Keeping that on mind, when you multiply the polynomials shown in the figure attached, the result is:

 (x-6)(x^2+2x-4)

 x^3-4x^2-16x+24
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A circle has its center at (-1, 2) and a radius of 3 units. What is the equation of the circle? (1 point) (x - 1)2 + (y + 2)2 =
Nina [5.8K]

Answer:

(x + 1)^2 + (y - 2)^2 = 3^2 = 9

Step-by-step explanation:

The standard equation of a circle with center at (h, k) and radius r is

(x - h)^2 + (y - k)^2 = r^2.

Here, h = -1, k = 2 and r = 3, so the equation of this particular circle is

(x + 1)^2 + (y - 2)^2 = 3^2 = 9.

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3 years ago
Express 3080 as a product of prime factors
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Prime Factors of 3080 =2, 2, 2, 5, 7, 11

Which is the same as = 23 x 5 x 7 x 11

Prime Factors Tree of 3080

3080
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2 1540
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An arithmetic sequence with a third term of 8 and a constant difference of 5
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\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad  \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\ \hrulefill\\[0.5em] a_3=8\\ n=3\\ d=5 \end{cases} \\\\\\ a_3=a_1+(3-1)5\implies 8=a_1+(2)5 \\\\\\ 8=a_1+10\implies -2=a_1 \\\\\\ \begin{cases} a_1=-2\\ d=5 \end{cases}\implies a_n=-2+(n-1)d

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3 years ago
Which of the following is an even function? A.f(x) =(x-1)^2 b. F(x)=8x c.f(x) =x^2-x d.f(x)=7
pentagon [3]

Answer:

Step-by-step explanation:

A.f(x) =(x-1)^2  is even because of that even exponent, 2.

b. F(x)=8x  is odd because x has the exponent 1.

c.f(x) =x^2-x   is neither even nor odd

d.f(x)=7    is even because the exponent is even:  7^0

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3 years ago
If f(x) =4x-2 and g(x) =2x+8, what is h (x) when h (x) =f (x) +g(x)
melisa1 [442]

Answer:

h(x)=4x_2+2x+8

h(x)=6x+6

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