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boyakko [2]
4 years ago
5

Hey there i posted picture of question can you help please

Mathematics
1 answer:
Alexeev081 [22]4 years ago
8 0
1. To solve this problem you must apply the proccedure shown below:

2. When you multiply two polynomials, you must apply the distributive property and multiply the coefficients and add the exponents. For example:

 (x)(x^2)

 The coefficients of both terms are 1 and the sum of the exponents is 3= (1+2=3)

 Therefore:

  (x)(x^2)=x^3

 3. Keeping that on mind, when you multiply the polynomials shown in the figure attached, the result is:

 (x-6)(x^2+2x-4)

 x^3-4x^2-16x+24
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Step-by-step explanation:

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2 years ago
1<br> What is the solution to the equation 5x + 4 =19
ivolga24 [154]

Answer:

x=3

Step-by-step explanation:

5x + 4 = 19

     -4     -4

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3 years ago
Select the choice that translates the following verbal phrase correctly to algebra:
likoan [24]
The answer is <span>one halfn − 16
</span>
Let the number be n.

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</span><span>decreased by 16 is (-16)

</span><span>one half of a number decreased by 16 is
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3 years ago
Which polynomial can be simplified to a difference of squares
Mrrafil [7]
<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)

<h2>Why?</h2>

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

First=10a^{2}

Second=16a^{2}

Third=25a^{2}

Fourth=24a^{2}

We have that the coefficients of the quadratic terms that can be obtained by squaring are:

16a^{2} =(4a)^{2} \\\\25a^{2} =(5a)^{2}

The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.

So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}

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3 years ago
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Step-by-step explanation:

can we have the picture of the graph?

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