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Elena L [17]
3 years ago
5

A circle has its center at (-1, 2) and a radius of 3 units. What is the equation of the circle? (1 point) (x - 1)2 + (y + 2)2 =

3 (x + 1)2 + (y - 2)2 = 3 (x + 1)2 + (y + 2)2 = 9 (x + 1)2 + (y - 2)2 = 9
Mathematics
1 answer:
Nina [5.8K]3 years ago
8 0

Answer:

(x + 1)^2 + (y - 2)^2 = 3^2 = 9

Step-by-step explanation:

The standard equation of a circle with center at (h, k) and radius r is

(x - h)^2 + (y - k)^2 = r^2.

Here, h = -1, k = 2 and r = 3, so the equation of this particular circle is

(x + 1)^2 + (y - 2)^2 = 3^2 = 9.

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Evaluate the function for x = 2 and x = 6 f(x) = -(x - 2)​
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Answer:

f(2) = 0 and f(6) = -4

Step-by-step explanation:

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2 years ago
Which ordered pairs is a solution to −5x + 3y > 12?
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<u>Answer </u><u>:</u><u>-</u>

Given inequality ,

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  • 3y > 5x + 12
  • y > 5/3x + 12/3
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<u>When </u><u>x </u><u>is </u><u>3</u><u> </u><u>and </u><u>y </u><u>=</u><u> </u><u>9</u>

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<u>When</u><u> </u><u>x </u><u>is </u><u>-</u><u>5</u><u> </u><u>y</u><u> </u><u>is </u><u>5</u><u> </u>

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<u>When </u><u>x </u><u>is </u><u>3</u><u> </u><u>y </u><u>is </u><u>-</u><u>6</u><u> </u>

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<u>When </u><u>x </u><u>is </u><u>-</u><u>2</u><u> </u><u>y </u><u>is </u><u>-</u><u>5</u><u> </u>

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<u>When </u><u>x </u><u>is </u><u>2</u><u> </u><u>y </u><u>is </u><u>8</u><u> </u>

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<u>When</u><u> </u><u>x </u><u>is </u><u>-</u><u>6</u><u> </u><u>y </u><u>is </u><u>0</u><u> </u>

  • y > -10 +4
  • 0 > -6 ( possible )
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