Question

A circle has its center at (-1, 2) and a radius of 3 units. What is the equation of the circle? (1 point) (x - 1)2 + (y + 2)2 = 3 (x + 1)2 + (y - 2)2 = 3 (x + 1)2 + (y + 2)2 = 9 (x + 1)2 + (y - 2)2 = 9

Answer 1

Answer:

(x + 1)^2 + (y - 2)^2 = 3^2 = 9

Step-by-step explanation:

The standard equation of a circle with center at (h, k) and radius r is

(x - h)^2 + (y - k)^2 = r^2.

Here, h = -1, k = 2 and r = 3, so the equation of this particular circle is

(x + 1)^2 + (y - 2)^2 = 3^2 = 9.