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Yuri [45]
4 years ago
15

Piper is deciding between two truck rental companies. Company A charges an initial fee of $35 for the rental plus $3 per mile dr

iven. Company B charges an initial fee of $80 for the rental plus $2 per mile driven. Let AA represent the amount Company A would charge if Piper drives xx miles, and let BB represent the amount Company B would charge if Piper drives xx miles. Write an equation for each situation, in terms of x,x, and determine the interval of miles driven, x,x, for which Company A is cheaper than Company B.
Mathematics
1 answer:
vazorg [7]4 years ago
5 0

Answer:

An equation for each situation, in terms of x

A = 35 + 3x

B = 80 + 2x

The interval of miles driven x, for which Company A is cheaper than Company B is 0 to 44.9 miles.

Step-by-step explanation:

Let A represent the amount Company A would charge if Piper drives x miles

Let B represent the amount Company B would charge if Piper drives x miles.

Company A charges an initial fee of $35 for the rental plus $3 per mile driven.

A= $35 + $3 × x

A = 35 + 3x

Company B charges an initial fee of $80 for the rental plus $2 per mile driven.

B = $80 + $2 × x

B = 80 + 2x

The interval of miles driven x, for which Company A is cheaper than Company B.

= A < B

35 + 3x < 80 + 2x

3x - 2x < 80 - 35

x < 45 miles

That is: any number of miles driven below 45 miles makes Company A cheaper than Company B

The interval of miles driven x, for which Company A is cheaper than Company B is 0 to 44.9 miles.

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If f(x)=12x+2(x-1), find f(6)
zavuch27 [327]

Answer:

12x6+2(6-1)

72+2x5

72+10

82

82 is the answer.

Step-by-step explanation:

Just replace the X's in the problem with 6.

5 0
4 years ago
Nadia compares the weights, in grams, of some apples and oranges she find the median abs interquartile range of the weights.
choli [55]

Answer:

Apple

Orange

Step-by-step explanation:

Apple has the greater median with a median value of 150 which is more than that of orange at 130

The sample with the greater variability is the orange sample as the interquartile range value of 11 is greater Than 8 for Apple.

Yes it is possible, because of the greater variation on weight shown by the sample of oranges, then it could be possible.

3 0
3 years ago
Is the sequence below arithmetic or geometric? Explain
Korvikt [17]

Answer: its geometric

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8 0
3 years ago
7. License Plate Laws The Chapter Problem involved passenger cars in Connecticut and passenger cars in New York, but here we con
sergejj [24]

Yes it is true that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars because null hypothesis is rejected.

Given among 2049 Connecticut passenger cars, 239 had only rear license plates. Among 334 Connecticut trucks, 45 had only rear license plates.

let p_{1} be the probability that commercial cars have rear license plates and p_{2} be the probability that connected trucks have rear license plates.

                         Cars                     Trucks                         Total

Total                  2049                    334                             2383

x                          239                      45                                284

p                        0.1166                   0.1347                          0.1191

α=0.05

Hypothesis will be  :

H_{0}:p_{1} =p_{2}

H_{1} :p_{1} < p_{2}

It is a left tailed test at 0.05 significance.

Standard errors of p=\sqrt{p(1-p)/n}

=\sqrt{(0.1191*0.8809)/2383}

=\sqrt{0.1049/2383}        

=0.0066

Test statistic Z=p difference/standard error

=(0.1166-0.1347)/0.0066

=-0.0181/0.0061

=-2.967

p value=0.001505<5%

Since p is less than 5% we reject null hypothesis.

We cannot calculate standard deviation so  we cannot calculate confidence interval.

Hence there is statistical evidence at 5% significance level to support that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars.

Learn more about z test at brainly.com/question/14453510

#SPJ4

5 0
2 years ago
1/2(6 2/3+1/4)-5/24=
Helen [10]

For this case we must simplify the following expression:

\frac {1} {2} (6 \frac {2} {3} + \frac {1} {4}) - \frac {5} {24} =

We convert the mixed number to an improper fraction:

6 \frac {2} {3} = \frac {3 * 6 + 2} {3} = \frac {20} {3}

So, by rewriting we have:

\frac {1} {2} (\frac {20} {3} + \frac {1} {4}) - \frac {5} {24} =\\\frac {1} {2} (\frac {4 * 20 + 3 * 1} {4 * 3}) - \frac {5} {24} =\\\frac {1} {2} (\frac {80 + 3} {12}) - \frac {5} {24} =\\\frac {1} {2} (\frac {83} {12}) - \frac {5} {24} =

\frac {83} {24} - \frac {5} {24} =\\\frac {83-5} {24} =\\\frac {78} {24} =\\\frac {39} {12} =\\\frac {13} {4} =\\3 \frac {1} {4}

Answer:

3 \frac {1} {4}

5 0
3 years ago
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