Let's convert 8 pounds and 3 ounces, into all ounces.
So we know one pound = 16 ounces.
1 lb = 16 oz.
Now since Omar is 8 pounds + 3 ounces, we multiply 16 by 8, and add on the 3:
16 * 8 = 128
128 + 3 = 131
So Omar weights 131 ounces when he was born.
Now Omar has to gain 5 ounces each week, for 4 weeks. This means in total, he'll have to gain 5*4=20 ounces in 4 weeks.
Add them together:
131 + 20 = 151 oz OR 9 7/16 lb.
The equation is:
y = 10 sin(π/15 t) + 30
where 30 represents the initial height of the blade above the ground and π/15 represents the period as we are given that the blade completes two rotation every minute.Finally the 10 represents the length of the blades.
Hope this helps :)
Answer:
Step-by-step explanation:
Part A
Cost = T - (15/100) * T
Cost = (85/100)*T
Part B
You are asked to take 15% off the cost of something. The first equation is very clear how to do that -- just take 15% of T away from T
The second part is not so obvious if you are not familiar with it, but the result will be the same.
Start with the first equation
Cost = T - (15/100) T Change 1 T to 100 / 100
Cost = 100*T/100T - 15/100T
Cost = 85 /100 * T
Part C
Cost = Phone - 14 at Top quality. Red in Graph below
Cost = 75/100 * Phone at Big value. Blue in Graph belos
The graph below is a good way to answer this. I won't solve it algebraically when the graph will give you a much better idea which phone to get.
Answer: Up to a phone cost of 55 dollars, the red phone is the better buy.
After 55$ the blue phone is better.
Try this with a couple of values for phone,
Answer 1: For the Parallelogram inside the rectangle the area = 48
Rectangle = 275 275+48 = 323
Answer 2: For the answer for the square inside the parallelogram = 36
The answer to the parallelogram = 120 120+36 = 156
Step-by-step explanation: #1: A = bh = 12 · 4 = 48
A = wl = 11 · 25 = 275
#2: A = a2 = 62 = 36
A = bh = 15 · 8 = 120
Sorry if u didn't have to add im not to good at this ;(
Hope that helped though!
y > -3x + 1
This answer is certified correct because I took the quiz
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