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Simora [160]
3 years ago
12

What is range of 34,56,13,98, and 75? A) 23 B) 85 C) 56 D) 55.2

Mathematics
2 answers:
nadezda [96]3 years ago
7 0

Answer:

Range is 85

Step-by-step explanation:

First you need to know the definition of range which is the biggest number minus the smallest number.

Biggest #: 98          Smallest #: 13

so you'd do 98-13 which is 85

GenaCL600 [577]3 years ago
6 0

Answer: B; 85


Step-by-step explanation

hope it help

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PLZZ HELP ME ITD MEAN THE WORLD
SSSSS [86.1K]

Answer: 33/3

Step-by-step explanation:

I don't know the question is weird but it probably is 33/3

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3 years ago
Find the value of k such that lim-->4 (x^2+x-k)/(x-4) exists
7nadin3 [17]

Answer:

k=20

Step-by-step explanation:

when x approaches 4, the denominator x-4 approaches 0

if the denominator is 0, it means that this is invalid

if the function is a number over 0 when x=4, it represents a vertical asymptote, which means no limit

so the only way possible to let there be a limit is to let the function be 0/0 when we plug in x=4

so x^2 + x - k = 0 when x = 4

4^2 + 4 - k = 0 ==> 20 - k = 0 ==> k = 20

6 0
2 years ago
Which polynomial action could be represented by the graph below?
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3 years ago
Joanna is paid $14 per hour is it linear
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8 0
3 years ago
Literally noone answers my questions please help
prohojiy [21]

Answers:

  • slower train = 139 km per hour
  • faster train = 159 km per hour

=================================================

Explanation:

x = rate of the slower train

x+20 = rate of the faster train

rates are in km per hour, abbreviated as kph

The train traveling at x kph will travel 5x km after 5 hours.

Use this formula

distance = rate*time

Using that same formula, the faster train travels 5(x+20) = 5x+100 kilometers in 5 hours.

The two distances must add to 1490 if we want the trains to pass by each other. Assume that the trains are traveling on parallel side-by-side tracks.

--------------------------

So,

(slower train distance) + (faster train distance) = 1490

(5x) + (5x+100) = 1490

10x+100 = 1490

10x = 1490-100

10x = 1390

x = 1390/10

x = 139

The slower train moves at a rate of 139 km per hour.

x+20 = 139+20 = 159

The faster train moves at a speed of 159 km per hour.

--------------------------

Check:

The slower train travels 139 kph and travels for 5 hours, so it covers a distance of 139*5 = 695 km

The faster train has a speed of 159 kph and travels for 5 hours, so it covers 159*5 = 795 km

Total distance = 695+795 = 1490

The answers are confirmed.

7 0
2 years ago
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