Y=x^2+10x+11
y=x^2+x-7
therefore,
x^2+10x+11=x^2+x-7
x^+10x+11-x^2-x+7=0
9x+18=0
x=-2
y=(-2)^2+10(-2)+11= -5
Answer:
<u>Radius: 12 units </u>
- Area: πr² = 3.14*12² = 452.16 square units
<u>Diameter: 16.8 units</u>
- Area: πd²/4 = 3.14*16.8²/4 = 221.5584 square units
<u>Radius: 3.4 units</u>
- Area: πr² = 3.14*3.4² = 452.16 square units
<u>Diameter: 10 units</u>
- Area: πd²/4 = 3.14*10²/4 = 78.5 square units
C. 01/100. .01 is in the hundredths place. So you put 2 0's on the denominator.
1 ÷ 4 1/4 so one lap is a quarter of a mile meaning 3 laps is 3/4 of a mile
The perpendicular line will have the x and y coefficients swapped and one of them negated. We can write the desired line as
9(x -6) -3(y -4) = 0
where the coordinates of the point of interest are (6, 4).
Dividing by 3, this is
3(x -6) -(y -4) = 0
3x -y = 14
An equation for the line of interest is ...
3x -y = 14