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2 years ago

Solve the equation -10 + 3x + 5x = -56 ? ??

2 answers:

8 0

Add like terms on the same side:
-10 + 8x = -56
Add ten to both sides
-10 + 8x + 10 = -56 +10
Simplify:
8x = -46
Divide both side by 8
8x/8 = -46/8
Simplify
x = - 5.75
The answer is x = -5.75
(The answer can also be written as -23/4 or -5 3/4)

Triss [41]2 years ago

7 0

Let's solve your equation step-by-step.−10+3x+5x=−56
Step 1: Simplify both sides of the equation.
8x−10=−56
Step 2: Add 10 to both sides.
8x−10+10=−56+108x=−46
Step 3: Divide both sides by
8.8x8=−468
x=−23/4

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3 years ago

Read 2 more answers

Simplify the expression -2+6.45z-6+(-3.25z)

erik [133]

Answer:

-8 + 3.2z

Step-by-step explanation:

when there is a "+" in front of an expression in parentheses, the expression remains the same
-2 + 6.45z - 6 - 3.25z
calculate the difference

-8 + 6.45z - 3.25z

collect like terms

-8 + 3.2z

8 0

2 years ago

3 + 1 < 10 solve, then graph the solution

ryzh [129]

3 + 1 < 10

There's no question there, and nothing to solve. That's a simple statement
which, after simplifying it slightly, says " 4 < 10 ".

A statement with which, I'm sure, we can all agree.

3 0

3 years ago

Find the angle between u =the square root of 5i-8j and v =the square root of 5i+j.

fenix001 [56]

Answer:

The angle between vector $\vec{u} = 5\, \vec{i} - 8\, \vec{j}$ and $\vec{v} = 5\, \vec{i} + \, \vec{j}$ is approximately $1.21$ radians, which is equivalent to approximately $69.3^\circ$ .

Step-by-step explanation:

The angle between two vectors can be found from the ratio between:

their dot products, and
the product of their lengths.

To be precise, if $\theta$ denotes the angle between $\vec{u}$ and $\vec{v}$ (assume that $0^\circ \le \theta < 180^\circ$ or equivalently $0 \le \theta < \pi$ ,) then:

$\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ .

<h3>Dot product of the two vectors</h3>

The first component of $\vec{u}$ is $5$ and the first component of $\vec{v}$ is also

The second component of $\vec{u}$ is $(-8)$ while the second component of $\vec{v}$ is $1$ . The product of these two second components is $(-8) \times 1= (-8)$ .

The dot product of $\vec{u}$ and $\vec{v}$ will thus be:

$\begin{aligned} \vec{u} \cdot \vec{v} = 5 \times 5 + (-8) \times1 = 17 \end{aligned}$ .

<h3>Lengths of the two vectors</h3>

Apply the Pythagorean Theorem to both $\vec{u}$ and $\vec{v}$ :

$\| u \| = \sqrt{5^2 + (-8)^2} = \sqrt{89}$ .
$\| v \| = \sqrt{5^2 + 1^2} = \sqrt{26}$ .

<h3>Angle between the two vectors</h3>

Let $\theta$ represent the angle between $\vec{u}$ and $\vec{v}$ . Apply the formula $\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ to find the cosine of this angle:

$\begin{aligned} \cos(\theta)&= \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} = \frac{17}{\sqrt{89}\cdot \sqrt{26}}\end{aligned}$ .

Since $\theta$ is the angle between two vectors, its value should be between $0\; \rm radians$ and $\pi \; \rm radians$ ( $0^\circ$ and $180^\circ$ .) That is: $0 \le \theta < \pi$ and $0^\circ \le \theta < 180^\circ$ . Apply the arccosine function (the inverse of the cosine function) to find the value of $\theta$ :

$\displaystyle \cos^{-1}\left(\frac{17}{\sqrt{89}\cdot \sqrt{26}}\right) \approx 1.21 \;\rm radians \approx 69.3^\circ$ .

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2 years ago

Any help is appreciated, this is timed :)

tekilochka [14]

Answer:

step 6 has an algebraic error

7 0

2 years ago