1+(21/100) = 1.21
15049 * 1.21 = 18209.29 (rounded to 18209)
The population was 18209
Hope this helps! :)
We need to get x by itself.
We do that by subtracting 5 from both sides.
This leaves us with <em>x = -7</em>.
So x = -7 is the solution.
Vertex form is f(x) = a(x - b)^2 + c where the vertex is (b, c) and a is some constant.
So for the first part we have f(x) = a(x + 6)^2 - 1
for root -9:- a( -9+6)^2 - 1 = 0
9a - 1 = 0 , a = 1/9
The other 3 are derived in the same way.
so required equation is f(x) = (1/9)(x + 6)^2 - 1
Answer:
a) 229 and 305 days
b) 229 days or less
c) 305 days or more
Step-by-step explanation:
The Empirical Rule(68-95-99.7 rule) states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 267
Standard deviation = 19
(a) Between what values do the lengths of the middle 95% of all pregnancies fall?_____________and___________days
By the Empirical rule, 95% of all pregnancies fall within 2 standard deviations of the mean.
So
267 - 2*19 = 229 days
to
267 + 2*19 = 305 days
(b) How short are the shortest 2.5% of all pregnancies?______days or less
95% of all pregnancies fall within 2 standard deviations of the mean. The other 5% are more than 2 standard deviations from the mean. Since the distribution is symmetric, 2.5% is more than 2 standard deviations below the mean(shortest 2.5%) and 2.5% is more than 2 standard deviations above the mean(longest 2.5%). So
267 - 2*19 = 229 days
c) How long do the longest 2.5% of pregnancies last?________days or more
Explanation in b)
267 + 2*19 = 305 days
Answer:
3t - 16
Step-by-step explanation:
(18/12 t-8)*2
First simplify inside the parentheses
(3/2 t -8)*2
Then multiply
3/2t *2 -8*2
3t - 16
