Answer:

Step-by-step explanation:
We can find the slope (m) by using coordinate pairs of any 2 points located along the slope of the line that we have on the graph.
This, let's use the coordinate pairs at:
x = -4, y = 2 (-4, 2) => (x2, y2)
x = 0, y = -4 (0, -4) => (x1, y1)






Answer:

Step-by-step explanation:
We are given;
- The equation of a line 6x-2y=4+6y
- A point (8, -16)
We are required to determine the equation of a line parallel to the given line and passing through the given point.
- One way we can determine the equation of a line is when we are given its slope and a point where it is passing through,
First we get the slope of the line from the equation given;
- We write the equation in the form y = mx + c, where m is the slope
That is;
6x-2y=4+6y
6y + 2y = 6x-4
8y = 6x -4
We get, y = 3/4 x - 4
Therefore, the slope, m₁ = 3/4
But; for parallel lines m₁=m₂
Therefore, the slope of the line in question, m₂ = 3/4
To get the equation of the line;
We take a point (x, y) and the point (8, -16) together with the slope;
That is;


Thus, the equation required is 
Answer:
Step-by-step explanation:
I'm assuming you're trying to solve this for x. We use the difference identity for cosine and rewrite:
and simplify using the unit circle to help.

and on the unit circle, the angle where the tangent is negative square root of 3 is -60° which is also a positive 300°
Answer:
4/20 or 1/5 if you want it simplified