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Marina CMI [18]
3 years ago
6

Please show your work What is the solution of the equation

x" id="TexFormula1" title=" \sqrt{2x+13} -5=x" alt=" \sqrt{2x+13} -5=x" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Hatshy [7]3 years ago
3 0
Add the five to each side.
then square it to get rid of the square root
2x+13=(5+x)^2
2x+13=x^2+10x+25
2x=x^2+10x+12
x^2+8x+12=0
(x+6)(x+2)
x+6=0
x+2=0
answers are -2 and -6, however, when pluging -6 in it doesnt work, so it is only -2.
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0.4 in fraction form. Please
Digiron [165]

Answer:

4/10

Step-by-step explanation:

0.4 is said by "four-tenths." Fractions are also said the same way. Notice how there is a four and a ten. This should be easier to help you make decimals in fraction form. The four would be the numerator and the ten would be the denominator, making the final answer 4/10.

5 0
3 years ago
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Find the solution of the square root of the quantity of x plus 2 plus 4 equals 8, and determine if it is an extraneous solution
Iteru [2.4K]

Consider the equation:

\sqrt{x+2}+4 = 8

Subtracting '4' from both the sides of the equation, we get as

\sqrt{x+2}+4-4= 8-4

\sqrt{x+2}= 4

Squaring on both the sides of the equation, we get

(\sqrt{x+2})^2 = (4)^2

x+2 = 16

Subtracting '2' from both the sides of the equation, we get

x+2-2=16-2

x=14

Since, An extraneous solution is a solution that arises from the solving process that is not really a solution at all. But, in this equation x=14 is the solution of the given equation.

Hence, it is not an extraneous solution.

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3 years ago
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Jose bought a bag of 6 oranges for $2.82. He also bought 5 pineapples. He gave the cashier $20 and received $1.43 change. How mu
svp [43]
Your answer is: $3.15 each.

Here are the steps:

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Answer:

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