Answer:
Choice B
Step-by-step explanation:
The first step is to write the polar equation of the conic section in standard form by dividing the numerator and denominator by 6;
The eccentricity of this conic section is thus 2/3, the coefficient of cos theta. Clearly, the eccentricity is between o and 1 implying that this conic section represents an Ellipse.
Lastly, the ellipse will open towards the left since we have positive cos theta in the denominator. The only graph that meets the conditions is graph B.
Answer:
a^2 + b^2 = c^2, where c is the hypotenus and a and b are the legs
Step-by-step explanation:
<h3>
Answer: 24 (choice C)</h3>
Assuming M is a midpoint of KW, this means that WM and KM are congruent
WM = KM
x+3 = 2(x-3) ... substitution
x+3 = 2x-6
2x-6 = x+3
2x-6-x = x+3-x .... subtract x from both sides
x-6 = 3
x-6+6 = 3+6 ... add 6 to both sides
x = 9
Use x = 9 to find the length of WM
WM = x+3 = 9+3 = 12
Which can be used to find the length of KM as well
KM = 2(x-3) = 2(9-3) = 2(6) = 12
both lengths are the same (12) as expected
This makes WK to be
WK = WM + KM
WK = 12 + 12
WK = 24
<h3>
Answer: 282.6 square units</h3>
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Work Shown:
r = 3 is the radius of the circular base
h = 12 is the height of the cylinder
pi = 3.14 approximately
SA = surface area of the cylinder
SA = 2pi*r^2 + 2pi*r*h
SA = 2*3.14*3^2 + 2*3.14*3*12
SA = 282.6
