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Phoenix [80]
4 years ago
10

If the perimeter of the triangle below is 28/3 what is the length of the side labeled 'x' ​

Mathematics
1 answer:
notsponge [240]4 years ago
4 0

Answer:

2

Step-by-step explanation:

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What is the coefficient in this expression? 5-4.7-2x+5/8
Marizza181 [45]

In 5-4.7-2x+5/8 there is only one term containing a variable: -2x. The coefficient is the (negative) numeral -2.

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3 years ago
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Please help, very hard question (for me), Will give Brainliest!!!
AleksAgata [21]
The answer is D. This is because when you take 10.65 and subtract 9.95 from it you get 0.07. If you take this number and continuously add to 9.95 you get the numbers provided in the chart. We'll also notice that the 0.07 is only added after 10 minutes of talking (10,20,30,etc.).
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4 years ago
What would the answer to this be?
s344n2d4d5 [400]
<u>STEPS:</u>

1) set up an equation. use x as a variable
       
      2x + 3x = 25

2) solve the equation for x:

      5x = 25
      x = 5


3) Now that you know the value of x, substitute it into the expression for how any girls there are, which is "3x" (since the ratio of BOYS to GIRLS is 2:3):

      3x
      = 3(5)
      = 15


So 15 is your answer, and there are <u>15 girls in the class.</u>
4 0
3 years ago
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Will a circle always have a greater area than a square if the circumfrance and perimeter are the same
daser333 [38]
The answer is yes. here is how:
circumference of a circle is 2pi*r
perimeter of a square is 4a, a being the length of each side.
when 2pi*r=4a, r=(2a)/pi
area of the circle is pi*r^2=pi(2a/pi)^2=(4/pi)*a^2
area of the square is a^2
Because 4/pi is bigger than 1, (4/pi)*a^2 is always larger than a^2
6 0
4 years ago
2. Quadrilateral ABCD is inscribed in a circle. Find the measure of each of the angles of the quadrilateral. Show your work.
sasho [114]

A cyclic quadrilateral is a quadrilateral whose vertices all touch the circumference of a circle.

Opposite angles in a cyclic quadrilateral add to 180 degrees. Quadrilateral ABCD is a cyclic quadrilateral.

< A+<C=180

Substituting <A and <B values given in figure:

x+2+x-2=180

Adding like terms:

2x=180

Dividing both sides by 2

x=90°

<A=x+2=90+2=92°

<C=x-2=90-2=88°

<D=x-10=90-10=80°

<B+<D=180

<B=180-80=100°

The angles of the quadrilateral ABCD are

<A=92°

<B=100°

<C=88°

<D=80°

4 0
4 years ago
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