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jeyben [28]
3 years ago
5

The function f(x) = 5()x is reflected over the y-axis. Which equations represent the reflected function? Check all that apply.

Mathematics
2 answers:
s344n2d4d5 [400]3 years ago
5 0

Answer:

The correct option is D.  f(x) = 5()-x

Step-by-step explanation:

If a function f(x) is reflected over axis then the resultant equation of the function f(x) changes to f(-x)

Now, in the given problem the function is given to be : f(x) = 5()x

So, if we reflect the given function f(x) over the y- axis then the equation of the function changes to f(-x)

Hence, The required reflected equation of the given function f(x) is 5()-x

Therefore, The correct option is D.  f(x) = 5()-x

Taya2010 [7]3 years ago
3 0
Key term "Reflected", which is equivalent to "inverse". This means that the graph, although remains with the same points, is "reflected". Think of a mirror. 
Say y = m(x). The reflected result is y = -m(x). Or in another case, y = m(-x) will be reflected to y = m(x). 
Lets break this rule further. Say your point was (a,b) which is code for (x,y). If we're looking at the x-axis, the y becomes negative. Henceforth, it becomes (x,-y) and vice versa. 
In this case, we're looking at the y-axis reflected, meaning, the x-value will be NEGATIVE. 

Answer is C: m(x) - 5() -x This can be seen as m(x) = m(-x) as well.
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Vlada [557]

Answer:

(1) The correct answer is option (a) 0.510

(2) The correct answer is option (b) = 0.9664

(3) The correct answer is option (a)  0.8665

Step-by-step explanation:

1. Find attached of question 1

2.

n= 850

p= 0.1400  

here mean of distribution(μ) =n*p

                                               =850* 0.1400

                                                = 119  

standard deviation σ = √(np(1-p))

                                    = √(850*0.1400(1-0.1400))

                                    = √102.34

                                       =10.1163  

for normal distribution z score =(X-μ)/σx    

therefore from normal approximation of binomial distribution and continuity correction:

probability = P(X>100.5)

                   = P(Z>-1.83)

                   = 1-P(Z<-1.83)

                   = 1-0.0336

                   = 0.9664

3.

n = 1000

p = 0.08

mean of distribution(μ) =np

                                       = 1000*0.08

                                        = 80

and standard deviation σ=√(np(1-p))

                                    = √(1000*0.08(1-0.08))

                                    = √736

                                    = 8.5790

probability = P(X>70.5)

                   = P(Z>-1.11)

                    = 1-P(Z<-1.11)

                    = 1-0.1335

                    = 0.8665

8 0
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