Given :
The Mad Hat Company must ship two different-sized boxes: The small ones cost them 45 cents each and weigh 6 ounces, and the large ones weigh 25 ounces and cost $1.20 each.
The total shipment this morning weighed 20 pounds 7 ounces and cost $18.45.
To Find :
How many packages of each size were shipped.
Solution :
We know, 1 pound = 16 ounces.
So, 20 pound = 20×16 = 320 ounces.
Let, number of large and small box are l and s.
So,
25l + 6s = 327 ...1)
0.45s + 1.20l = 18.45 ...2)
Solving both the equations, we get :
x = 9 and y = 17
Therefore, package smaller and big size are 17 and 9 respectively .
Hence, this is the required solution.
The present age of father is 86 years old and present age of son is 48 years old
<em><u>Solution:</u></em>
Given that, a father is now 38 years older than his son
Ten years ago he was twice as old as his son
Let "x" be the age of son now
Therefore, from given,
Father age now = 38 + age of son now
Father age now = 38 + x
<em><u>Ten years ago he was twice as old as his son</u></em>
Age of son ten years ago = age of son now - 10
Age of son ten years ago = x - 10
Age of father ten years ago = 38 + x - 10
Then we get,
Age of father ten years ago = twice the age of son ten years ago
38 + x - 10 = 2(x - 10)
28 + x = 2x - 20
2x - x = 28 + 20
x = 48
Thus son age now is 48 years old
Father age now = x + 38 = 48 + 38 = 86
Thus present age of father is 86 years old and present age of son is 48 years old
What about it? What is the question?
Answer:
10 weeks
Step-by-step explanation:
1 because 20 times 10 is 200 and if he starts with 500 then he can withdraw 20 dollars a week for 10 weeks to have 300 left by the end of the summer, hope this helps :)
