Answer:
E,D
Step-by-step explanation:
 
        
             
        
        
        
Answer:
Step-by-step explanation:
Method 1: Taking the log of both sides... 
So take the log of both sides... 
5^(2x + 1) = 25 
log 5^(2x + 1) = log 25 <-- use property: log (a^x) = x log a... 
(2x + 1)log 5 = log 25 <-- distribute log 5 inside the brackets... 
(2x)log 5 + log 5 = log 25 <-- subtract log 5 both sides of the equation... 
(2x)log 5 + log 5 - log 5 = log 25 - log 5 
(2x)log 5 = log (25/5) <-- use property: log a - log b = log (a/b) 
(2x)log 5 = log 5 <-- divide both sides by log 5 
(2x)log 5 / log 5 = log 5 / log 5 <--- this equals 1.. 
2x = 1
x=1/2
Method 2
5^(2x+1)=5^2
2x+1=2
2x=1
x=1/2
 
        
             
        
        
        
The answer to this is .15%