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Maurinko [17]
3 years ago
15

Given f’(x), where is f(x) increasing? Where is f(x) concave up?

Mathematics
1 answer:
Levart [38]3 years ago
3 0

Answer:

See explanation below

Step-by-step explanation:

a. f(x) is increasing at (-∞, 1] and [7, ∞) because f'(x) is positive at those intervals.

b. f(x) is concave up at [4, ∞) because the slope of f'(x) or f''(x) is positive.

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Answer:

Solution given:

opposite:9

adjacent: 12

\theta=?

Relationship between opposite and adjacent is given by tan angle

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Tan \theta=\frac{opposite} {adjacent}=\frac{9}{12}

Tan \theta=\frac{3}{4}

\theta=Tan^{-1}\frac{3}{4}

\bold{\theta=36.8°}

#11.

hypotenuse[h]=11cm

opposite/perpendicular[P]=b cm

adjacent/base[b]=a cm

now

\theta=62°

Relationship between height and hypotenuse is given by Sin angle

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Sin 62°=\frac{opposite}{hypotenuse}=\frac{b}{11}

doing crisscrossed multiplication

b=Sin 62°*11

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doing crisscrossed multiplication

a=Cos 62°×11

a=5.16cm

b) the distance between the foot of the ladder and the building is <u>5.16cm.</u>

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