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WITCHER [35]
3 years ago
10

You now have entered the math zone

Mathematics
2 answers:
Ostrovityanka [42]3 years ago
4 0

Answer:

12-12, it's a decrease so you subtract.

IrinaVladis [17]3 years ago
4 0
I believe it would be 12-12

Explanation:
It said the original temperature was 12 and that it decreased by 12 so fill in subtraction sign instead of decreased and you would have 12-12
You might be interested in
Help please explain the answer
Oksi-84 [34.3K]

The answer for x is 5x

5 0
3 years ago
For the love of God help me !! I'm desperate for it tomorrow
Eduardwww [97]
Try to relax.  Your desperation has surely progressed to the point where
you're unable to think clearly, and to agonize over it any further would only
cause you more pain and frustration.
I've never seen this kind of problem before.  But I arrived here in a calm state,
having just finished my dinner and spent a few minutes rubbing my dogs, and
I believe I've been able to crack the case.

Consider this:  (2)^a negative power = (1/2)^the same power but positive.

So: 
Whatever power (2) must be raised to, in order to reach some number 'N',
the same number 'N' can be reached by raising (1/2) to the same power
but negative.

What I just said in that paragraph was:  log₂ of(N) = <em>- </em>log(base 1/2) of (N) .
I think that's the big breakthrough here.
The rest is just turning the crank.

Now let's look at the problem:

log₂(x-1) + log(base 1/2) (x-2) = log₂(x)

Subtract  log₂(x)  from each side: 

log₂(x-1) - log₂(x) + log(base 1/2) (x-2) = 0

Subtract  log(base 1/2) (x-2)  from each side:

log₂(x-1) - log₂(x)  =  - log(base 1/2) (x-2)  Notice the negative on the right.

The left side is the same as  log₂[ (x-1)/x  ]

==> The right side is the same as  +log₂(x-2)

Now you have:  log₂[ (x-1)/x  ]  =  +log₂(x-2)

And that ugly [ log to the base of 1/2 ] is gone.

Take the antilog of each side:

(x-1)/x = x-2

Multiply each side by 'x' :  x - 1 = x² - 2x

Subtract (x-1) from each side:

x² - 2x - (x-1) = 0

x² - 3x + 1 = 0

Using the quadratic equation, the solutions to that are
x = 2.618
and
x = 0.382 .

I think you have to say that <em>x=2.618</em> is the solution to the original
log problem, and 0.382 has to be discarded, because there's an
(x-2) in the original problem, and (0.382 - 2) is negative, and
there's no such thing as the log of a negative number.


There,now.  Doesn't that feel better. 
 






4 0
3 years ago
A bus can carry 50 people per run. At least how many times does the bus have to run in order to transfer 25, 000 people?
galina1969 [7]
50 × 500 = 25,000

The answer is 500 runs.
7 0
3 years ago
Which dimensions can create more than one triangle? A. Three angles measuring 75°,45°, and 60°. B. 3 sides measuring 7, 10, 12?
NeTakaya

This is vague.  Any dimensions that make a triangle can make more than one, just draw another right next to it.  What's really being asked is which dimensions can make more than one non-congruent triangle.

<span>A. Three angles measuring 75°,45°, and 60°.

That's three angles, and 75+45+60 = 180, so it's a legit triangle. The angles don't determine the sides, so we have whole family of similar triangles with these dimensions.  TRUE

<span>B. 3 sides measuring 7, 10, 12?

</span>Three sides determine the triangles size and shape uniquely; FALSE

<em>C. Three angles measuring 40</em></span><span><em>°</em></span><em>, 50°</em><span><em>, and 60°? </em>

40+50+60=150, no such triangle exists.  FALSE

<em>D. 3 sides measuring 3,4,and 5</em>

Again, three sides uniquely determine a triangle's size and shape;  FALSE


</span>
7 0
3 years ago
Read 2 more answers
Which expression is equivalent to (4g3h2k4)3
RSB [31]

Answer:

d) 8g^{6}h^{4}  k^{12}  - (h^{25} k^{15} )

      \frac{(4g^{3} h^{2}k^{4} )^{3}  }{8g^{3}h^{2}  } - (h^{5} k^{3} )^{5}    = 8g^{6}h^{4}  k^{12}  - (h^{25} k^{15} )

Step-by-step explanation:

<u><em>Explanation</em></u>

Given expression

           =     \frac{(4g^{3} h^{2}k^{4} )^{3}  }{8g^{3}h^{2}  } - (h^{5} k^{3} )^{5}

By using

        (ab)ⁿ = aⁿbⁿ

         \frac{a^{m} }{a^{n} } = a^{m-n}

   =     \frac{(4)^{3} g^{9} h^{6}k^{12} )  }{8g^{3}h^{2}  } - (h^{5} k^{3} )^{5}

After simplification , we get

  = 8g^{9}g^{-3} h^{6} h^{-2} k^{12}  - (h^{5} k^{3} )^{5}

 = 8g^{9-3}h^{6-2}  k^{12}  - (h^{5} k^{3} )^{5}

= 8g^{6}h^{4}  k^{12}  - (h^{25} k^{15} )

3 0
3 years ago
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