U basically solve: (4sqrt8)*2 + (5 sqrt 12 + 6 sqrt 20)*2
Answer:
16.28 mph ; 79.38°
Step-by-step explanation:
Given the following :
Speed of child due east = 3mph
Speed of ship due North = 16mph
Relative speed of th child is obtained by using Pythagoras rule to find the hypotenus
Relative Speed = Sqrt(3² + 16²)
Relative Speed = sqrt(9 + 256)
= sqrt(265)
= 16.2788 mph
= 16.28 mph
From trigonometry ;
Tanθ = opposite / Adjacent
Tanθ = (16 / 3)
Tanθ = 5.333
θ = tan^-1(5.333)
θ = 79.379°
θ = 79.38°
A^2-5a = 6
a^2-5a-6 = 0
Discriminant = (-5)^2-4(1)(-6) = 49
Discriminant is positive so there are two solutions
Answer:
x = 4
Step-by-step explanation:
ΔTRQ is an isosceles right triangle, so if we find the value of RT then the value of 'x' will be the same
We can find RT by creating a proportion based on the ratio of sides in a 30-60-90° triangle which, respectively, is 1 :
: 2
2
/RT =
/2
cross-multiply:
· RT = 4
RT = 4
Therefore, x = 4
110% of 90 is 99, 1.1*90=99