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pentagon [3]
3 years ago
5

Dave bought 18 packets of cookies for $21.60. Each packet of cookies contains 20 cookies. find the cost of each cookie to the ne

arest tenth of a cent
Mathematics
1 answer:
zalisa [80]3 years ago
6 0

Answer:

16.7 cents for one cookie

Step-by-step explanation:

18 multiplied by 20 is 360. 360 divided by 21.60 equals 16. 66 which rounds to 16.7 cents per cookie

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Let r=.05 be the reserve rate. Which one of the following is the money multiplier?
Lady_Fox [76]
The formula for the money multiplier is :
1/ Reserve rate
so, the answer would be :
1/0.05
5 0
3 years ago
Read 2 more answers
I need help on these questions can u make sure u do all of them cuz some people just only do one problem.
ioda
Tuesday
1. positive
2. negative

thursday
she will pay $51.60

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8 0
2 years ago
Please help me!! I suck at geometry. I don’t understand any of it at all
zysi [14]

Answer:

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3 0
2 years ago
Find the quotient of <br><br> -85^2-27n+76 / -17n-19
bagirrra123 [75]
<u><em>Answer:</em></u>
5n-4

<u><em>Explanation:</em></u>
<u>The given expression is:</u>
\frac{-85n^2-27n+76}{-17n-19}

<u>1- Take the negative as a common factor from both the numerator and the denominator. This will give us:</u>
\frac{-(85n^2+27n-76)}{-(17n+19)}

<u>2- Cancel out the negative sign (common factor) from the numerator and denominator. This will give us:</u>
\frac{(85n^2+27n-76)}{(17n+19)}

<u>3- Factor the numerator. This wil give:</u>
\frac{(5n-4)(17n+19)}{(17n+19)}

<u>4- Finally, cancel out the (17n+19) which common in both numerator and denominator. This will give us the final expression:</u>
5n-4

Hope this helps :)
6 0
2 years ago
To test the effectiveness of a business school preparation course, 8 students took a general business test before and after the
Lisa [10]

Solution :

Group   Before     After

Mean    693.75    743.75

Sd         155.37     143.92

SEM        54.93     50.88

n              8            8

Null hypothesis : The preparation course not effective.

$H_0: \mu_d = 0$

Alternative hypothesis : The preparation course is effective in improving the exam scores.

$H_a : \mu_d>0$  (after -  before)

4 0
2 years ago
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