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2 years ago

14

Gilberto work 3 1/4 hours on Thursday 4 2/5 hours on Friday and 6 1/2 hours and Saturday how many hours did he work in all three

days

1 answer:

Illusion [34]2 years ago

7 0

Answer: He would work 14.15 hours in all

Add all the numbers up because it says "in all." Means you need to add

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A jewelry box is in the shape of a rectangular prism with an area of 528 cubic inches. The length of the box is 12 inches and th

Olin [163]

The height is 8 i believe

6 0

2 years ago

Can someone do this for me or help me

Elden [556K]

JM=12
JL= 14
MN=?
MK=?

VT= 11
UV= 9
RS=?
ST=?

GF=23
HF=20
GH=?
GE=?

M<1=?
M<2=?
M<3=?
M<4=?
M<5=?
M<6=?
M<7=?
M<8 = 90 degrees

WXZ = 34 degrees
WVZ=90 degrees
ZYW= 56 degrees

These are the only answers I knew, I’m sorry I couldn’t find the rest. If I do find more answers, I’ll comment them.

5 0

2 years ago

7. When dy/dx = (x -6)1/2, what does y equal?

Sergio039 [100]

The answer is below
$\frac{dy}{dx} = \frac{1}{2} (x - 6)$
multiply both sides by dx

$dy = \frac{1}{2} (x - 6)dx$
integrate both sides of the diffrential

$integral \: dy = integral \: \frac{1}{2} (x - 6)dx$
simplify and integrate to get y alone don't forget to tack on c with your indefinite integral

$y = \frac{x {}^{2} }{4} - 3x + c$

3 0

2 years ago

Can you solve this step by step please

cluponka [151]

Answer:

$(6.8 + 3.4) \times {10}^{6} \\ \\ 10.2 \times {10}^{6} \\ \\ 1.02 \times {10}^{7}$

I hope I helped you^_^

8 0

2 years ago

The Scottsdale fire department aims to respond to fire calls in 4 minutes or less, on average. Response times are normally distr

IgorC [24]

<h2><u>Answer with explanation</u>:</h2>

Let $\mu$ be the population mean.

As per given , we have

$H_0:\mu \leq4\\\\ H_a: \mu >4$

Since the alternative hypothesis is right-tailed , so the test is a right-tailed test.

Also, population standard deviation is given $\sigma=1$ , so we perform one-tailed z-test.

Test statistic : $z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

, where $\mu$ = Population mean

$\sigma$ = Population standard deviation

n= sample size

$\overline{x}$ = Sample mean

For n= 18 , $\overline{x}=4.50$ , $\sigma=1$ , $\mu =4$ , we have

$z=\dfrac{4.5-4}{\dfrac{1}{\sqrt{18}}}\approx2.12$

P-value (for right tailed test): P(z>2.12) = 1-P(z≤ 2.12) [∵ P(Z>z)=1-P(Z≤z)]\

=1- 0.0340=0.9660

Decision : Since P-value(0.9660) > Significance level (0.01), it means we are failed to reject the null hypothesis.

[We reject null hypothesis if p-value is larger than the significance level . ]

Conclusion : We do not have sufficient evidence to show that the goal is not being met at α = .01 .

3 0

2 years ago