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I am Lyosha [343]
4 years ago
9

would you prefer to purchase a cheap car which cost more to operate or to purchase a expensive car which cost less to operate? w

hy?
Mathematics
1 answer:
alexandr402 [8]4 years ago
5 0

Answer: Expensive car which cost less to operate.


Step-by-step explanation: When purchasing a new expensive car it is much more reliable, the risk you run with buying a used car is it breaking down on you while you are driving. Much less likely to happen with a new car.


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Solve 322 +63 +3=0 using the Quadratic Formula.<br> X=
Licemer1 [7]

Answer:

Step-by-step explanation:

322+63 ?= 0

385≠0

False

7 0
4 years ago
EASY 7TH GRADE MATH 6 out of 8 dentists recommend crest toothpaste. In a group of 156 dentists, how many of them recommend crest
Novay_Z [31]

Answer:

117

Step-by-step explanation:

6/8 = ?/156

156/8 = 19.5

19.5 x 6 = 117

6/8 = 117/156

3 0
3 years ago
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Ryan spent 24 months living in San Diego.
sertanlavr [38]

Answer:

nothing

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4 years ago
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Write (8a-^3) -2/3 in simplest form
Anna71 [15]

(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}

<em><u>Solution:</u></em>

<em><u>Given that,</u></em>

(8a^{-3})^{\frac{-2}{3}

We have to write in simplest form

<em><u>Use the following law of exponent</u></em>

(a^m)^n = a^{mn}

Using this, simplify the given expression

(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^{ -3 \times \frac{-2}{3}}\\\\Simplifying\ we\ get\\\\(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^2\\\\We\ know\ that\ 8 = 2^3\\\\Therefore\\\\(8a^{-3})^{\frac{-2}{3}} =2^3^{\frac{-2}{3}} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} =2^{-2} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}

Thus the given expression is simplified

8 0
3 years ago
Can someone help me solve x
evablogger [386]

Answer:6

Step-by-step explanation:solve the equation, you know that it equals 90 because the angle is 90

so 16x-6=90

+6 both sides

16x=96

divided by 16 both sides to isolate x

x=6

4 0
3 years ago
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