The answer would be (0,2) because as shown in the graph ab crosses the y-axis at (0,2)
Complex zeroes always occurs as conjugates.
For z = a + b i conjugate is: a - b i
Another zero is : 2 + 3 i.
Verification:
2 + 3 i + 3 - 3 i = - b/a
- b = 4, a = 1
( 2 + 3 i ) ( 2 - 3 i ) = c / a
4 - 9 i² = c / a
4 + 9 = c / a
c = 13
( x^4 - 4 x³ + 14 x² - 4 x + 13 ) : ( x² - 4 x + 13 ) = x² + 1
x² + 1 = 0
x² = -1, x = i, x = -i
The zeroes are: - i , i , 2 + 3 i, 2 - 3 i.
Answer:
One another zero of f ( x ) is 2 + 3 i.
No i cant it always needs 2 but one of the two can be 0
a) ∠CEA and ∠DEB are reflections of each other across point E, the intersection point of lines CD and AB. They are vertical angles.
b) ∠AED and ∠BED together form a straight line, so are a linear pair. That means they are adjacent and supplementary.
Answer:
option D
Step-by-step explanation:
for x intercept
the curve crosses the x asis at 1
then for y intercept it crosses the y axis at-2
that's all...have fun
