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IrinaK [193]
3 years ago
8

(3a2 + 2a - 2) - (a2 - 3a + 7)

Mathematics
1 answer:
drek231 [11]3 years ago
3 0
Remember to distribute invibile -1
simlify 2nd part
-(a^2-3a+7)=-1(a^2-3a+7)=-a^2+3a-7

now we have
3a^2+2a-2-a^2+3a-7=
3a^2-a^2+2a+3a-2-7=
2a^2+5a-9
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A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?
VladimirAG [237]

Answer:

\sigma = 5.5

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution \bar X and for this case we know that the distribution is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error would be:

\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}

And replacing we got:

\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611

Step-by-step explanation:

For this case we know the population deviation given by:

\sigma = 5.5

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution \bar X and for this case we know that the distribution is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error would be:

\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}

And replacing we got:

\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611

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