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IrinaK [193]
2 years ago
8

(3a2 + 2a - 2) - (a2 - 3a + 7)

Mathematics
1 answer:
drek231 [11]2 years ago
3 0
Remember to distribute invibile -1
simlify 2nd part
-(a^2-3a+7)=-1(a^2-3a+7)=-a^2+3a-7

now we have
3a^2+2a-2-a^2+3a-7=
3a^2-a^2+2a+3a-2-7=
2a^2+5a-9
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Please help if the value of (x+1)^2-3 is 22 what is the value of (x+1)^2-5
Finger [1]
We could solve for x, but notice that the same expression is being squared in both (x+1)

if (x+1)^2 - 3 = 22 then
  (x+1)^2 = 25

that would mean that (x+1)^2 - 5 = 25 - 5 = 20


7 0
3 years ago
The expressions 1.08s+1.02b predicts the end of the year value of a financial portfolio where S is the value of stocks and B is
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Answer:

We have  

Stock = $200

Bonds = $100

Substitute these values into 1.08s+1.02b, where 's' is stock and 'b' is bond

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Predicted end of year value is $318

Step-by-step explanation:

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Solve using the quadratic formula. Show all work. Write each solution in simplest form. No decimals.
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3 0
3 years ago
One month Tammy rented 2 movies and 6 video games for a total of $ 42 . The next month she rented 5 movies and 3 video games for
EastWind [94]

Answer:

The rental cost of one movie is $2.25 and the rental cost of one video game is $6.25

Step-by-step explanation:

Let the rental cost of 1 movie be m.

Let the rental cost of 1 video game be v.

One month, Tammy rented 2 movies and 6 video games for a total of $42. This means that:

2m + 6v = 42 ________ (1)

The next month she rented 5 movies and 3 video games for a total of $30. This means that:

5m + 3v = 30 _________(2)

We now have two simultaneous equations:

2m + 6v = 42 ________ (1)

5m + 3v = 30 _________(2)

Multiply (2) by 2, and we have:

2m + 6v = 42 __________ (1)

10m + 6v = 60 _________ (3)

Subtract (1) from (3):

 10m + 6v = 60

-<u> 2m + 6v = 42</u>

 <u>  8m     =     18</u>

=> m = 18 / 8

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Put the value of m back in (1):

2(2.25) + 6v = 42

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=> 6v = 42 - 4.5 = 37.5

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v = $6.25

Therefore, the rental cost of one movie is $2.25 and the rental cost of one video game is $6.25

5 0
3 years ago
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