The limit of the given function if 
is 64
<h3>Limit of a function</h3>
Given the following limit of a function expressed as;
We are to determine the value of the function
![\frac{1}{4} \lim_{x \to 0} [f(x)]^4](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%20%20%5Clim_%7Bx%20%5Cto%200%7D%20%5Bf%28x%29%5D%5E4)
This can also be expressed as
![\frac{1}{4} \lim_{x \to 0} [f(x)]^4\\ = \frac{1}{4}(4)^4 \\=1/4\times 256\\=64](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%20%20%5Clim_%7Bx%20%5Cto%200%7D%20%5Bf%28x%29%5D%5E4%5C%5C%20%3D%20%5Cfrac%7B1%7D%7B4%7D%284%29%5E4%20%5C%5C%3D1%2F4%5Ctimes%20256%5C%5C%3D64)
Hence the limit of the given function if is 64
Learn more on limit of a function here: brainly.com/question/23935467
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Answer:
radius = circumference ÷ 2× po
Step-by-step explanation:
the radius is 2.55 but it's not in ur options
Answer:
[(x + 6), (y + 1)]
Step-by-step explanation:
Vertices of the quadrilateral ABCD are,
A → (-5, 2)
B → (-3, 4)
C → (-2, 4)
D → (-1, 2)
By reflecting the given quadrilateral ABCD across x-axis to form the image quadrilateral A'B'C'D',
Rule for the reflection of a point across x-axis is,
(x, y) → (x , -y)
Coordinates of the image point A' will be,
A(-5, 2) → A'(-5, -2)
From the picture attached, point E is obtained by translation of point A'.
Rule for the translation of a point by h units right and k units up,
A'(x+h, y+k) → E(x', y')
By this rule,
A'(-5 + h, -2 + k) → E(1, -1)
By comparing coordinates of A' and E,
-5 + h = 1
h = 6
-2 + k = -1
k = 1
That means
Rule for the translation will be,
[(x + 6), (y + 1)]
Wouldnt it be a dot on the line right in between 75 and 76 pointing towards the left? im not sure
