You just have to divide 309 by 4.78 so it would =64.6443
Answer:
S (1 , 0)
T (7 , 1)
Step-by-step explanation:
If QRST is a parallelogram, P is the mid point of segment QS and segment RT.
Basic formula for mid-point of segment: ((x1+x2)/2 , (y1+y2)/2)
T (x₁ , y₁) S (x₂ , y₂) P (2 , 3) Q (3 , 6) R (-3 , 5)
2 = (x₁ + (-3))/2 x₁ = 7
3 = (y₁ + 5)/2 y₁ = 1
T (7 , 1)
2 = (x₂ + 3))/2 x₂ = 1
3 = (y₂ + 6)/2 y₂ = 0
S (1 , 0)
I'll start 18 and 22 for you, and you should then be able to do the rest on your own!
For 18, what we literally do is apply the distance formula for all the points and add them up. For B to C, we get the distance between them to be
sqrt((x1-x2)^2+(y1-y2)^2)=sqrt((0-4)^2+(3-(-1))^2)=sqrt((-4)^2+4^2)=sqrt(16+16)=sqrt(32). Repeat the process for C to E, E and F, and F to B then add the results up to get your answer!
For 22, since the area of a rectangle is length*width (we know given the right angles and that the opposite sides are equal in how long they are), we can multiply 2 perpendicular lines, for example, BC and CE to get sqrt(32)*sqrt(8)=16 as the area
Answer:
![3 \frac{4}{5}](https://tex.z-dn.net/?f=3%20%5Cfrac%7B4%7D%7B5%7D%20)
Step-by-step explanation:
1) Add the whole numbers first.
![3 + \frac{1}{5} + \frac{3}{5}](https://tex.z-dn.net/?f=3%20%20%2B%20%5Cfrac%7B1%7D%7B5%7D%20%20%2B%20%20%5Cfrac%7B3%7D%7B5%7D%20)
2) Join the denominators.
![3 + \frac{1 + 3}{5}](https://tex.z-dn.net/?f=3%20%2B%20%20%5Cfrac%7B1%20%2B%203%7D%7B5%7D%20)
3) Simplify.
![3 \frac{4}{5}](https://tex.z-dn.net/?f=3%20%5Cfrac%7B4%7D%7B5%7D%20)
hence, the answer is 3 4/5.
Answer:
One possibility is that;
g(x) = (x + 1)
while h(x) = 5x^3
Step-by-step explanation:
Here, we are told to find one possibility for f(x) and g(x)
The term h(x) = (Fog)(x) means that we are inserting g(x) into f(x) to give h(x)
Now let’s have it this way;
We can see that g(x) = (x + 1) , then h(x) = 5x^3
This is one possibility of the values of g(x) and h(x)