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3 years ago

PLEASE HELP ME ILL MARK AS BRAINLIEST

Mathematics

2 answers:

Gelneren [198K]3 years ago

5 0

0.05 ---> 1/18

square root of 0.25 ------> 0.05

1/7------> 0.142857 repeating

0.6 -------> 2/3

Alborosie3 years ago

5 0

Answer:

0.05 ---> 1/18

1/7 ---> 0.142857

0.6 ---> 2/3

0.25 ---> 0.05

Step-by-step explanation:

You might be interested in

Suppose xy=−4 and dy/dt=−3. Find dx/dt when x=−1.

user100 [1]

When x=-1: $\quad (-1)y=-4\qquad\to\qquad y=4\)$

Ok that gives us a little more information.
If we implicitly differentiate with respect to t, from the very start, then we can apply our product rule, ya?

$x'y+xy'=0$

The right side is zero, derivative of a constant is zero.
Where x' is dx/dt and y' is dy/dt.

From here, plug in all the stuff you know:
y' = -3
x = -1
y = 4

and solve for x'.

Hope that helps!

4 0

3 years ago

The table shows the height, in centimeters, that a weight bouncing from a spring would achieve if there were no friction, for a

Paha777 [63]

Hello! For ease of calculations, we can identify the time it took for the weight to bounce back to the other direction, then the other, and then back to its original position by looking at the time it took for the weight to change from 0 to 25 to 0 to -25 then back to 0. This is one whole cycle of the weight.

By the time the weight first reached zero, 1.5 seconds has passed. By the third time it got to zero again, 7.5 seconds has passed. Therefore, one whole cycle of the weight is 7.5-1.5 = 6.0 seconds.

ANSWER: One whole cycle of the weight took 6 seconds.

4 0

3 years ago

Please help me idk what it's even asking for

AveGali [126]

Answer:

It is asking you what you would put as your statement for step 4.

Step-by-step explanation:

The answer by the way would be what you have clicked on - angle 1 + angle 4 = 180 degrees.

4 0

3 years ago

Read 2 more answers

A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$

In point c)

$\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\$

In point d)

using standard normal variate

$x=20.17\\\\ z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17$

8 0

3 years ago

Could anyone help me answer this

BARSIC [14]

Answer:

the answer might be 150 ft

Step-by-step explanation:

adds on 30

hope that helps

please mark as brainliest if correct

thank you

19NBoli

3 0

3 years ago