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Lady bird [3.3K]
3 years ago
6

One type of technology that can verify a person's identity is _____.

Computers and Technology
2 answers:
Digiron [165]3 years ago
6 0

hello there

the answer is

Automated Fingerprint Verification

thank you

Juliette [100K]3 years ago
3 0

AFV (Automated Fingerprint Verification)

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Which of these consoles have 64 bit architecture
tigry1 [53]

I don't know if this is on your list, but I know for a fact that the Nintendo 64 system (or N64) has a 64-bit architecture.

8 0
3 years ago
Which system provides an easier way for people to communicate with a computer than a graphical user interface (GUI)
Marta_Voda [28]
Answer: natural Language Processing

Explanation:

Natural Language Processing: It is a sub field of linguistics which is concerned with the interactions between Human and computer especially how to program computers to process and to understand large amounts of natural language data.
6 0
3 years ago
Write a program that converts a number entered in Roman numerals to decimal. your program should consist of a class, say, Roman.
arlik [135]

Answer:

The code is given below in Java with appropriate comments

Explanation:

import java.util.*;

public class RomantoDecimal {

    public static void main(String[] args)

    {

         Scanner SC = new Scanner(System.in);

         RomantoDecimal r = new RomantoDecimal();

         System.out.println("Enter a Roman number :");

         // INPUT A ROMAN NUMBER

         String rNum = SC.next();

         // CALL convertToDecimal FOR CONVERSION OF ROMAN TO DECIMAL

         r.convertToDecimal(rNum);

    }

    // M=1000, D=500, C=100, L=50, X=10, V=5, I=1

    public void convertToDecimal(String roamNo)

    {

         int number = 0;

         // TEACK EACH DIGIT IN THE GIVEN NUMBER IN REVERSE ORDER

         for (int i = roamNo.length() - 1; i >= 0; i--)

         {

             // FIND OUT WHETHER IT IS 'M' OR NOT

             if (roamNo.charAt(i) == 'M')

             {

                  if (i != 0)

                  { // CHECK WHETHER THERE IS C BEFORE M

                       if (roamNo.charAt(i - 1) == 'C')

                       {

                            number = number + 900;

                            i--;

                            continue;

                       }

                  }

                  number = number + 1000;

             }

             // FIND OUT WHETHER IT IS 'D' OR NOT

             else if (roamNo.charAt(i) == 'D')

             {

                  if (i != 0)

                  {

                  // CHECK WHETHER THERE IS C BEFORE D

                       if (roamNo.charAt(i - 1) == 'C')

                       {

                            number = number + 400;

                            i--;

                            continue;

                       }

                 }

                  number = number + 500;

             }

            // FIND OUT WHETHER IT IS 'C' OR NOT

             else if (roamNo.charAt(i) == 'C')

             {

                  if (i != 0)

                  {

                       if (roamNo.charAt(i - 1) == 'X')

                       {

                            number = number + 90;

                            i--;

                            continue;

                      }

                  }

                  number = number + 100;

             }

             else if (roamNo.charAt(i) == 'L')

             {

                  if (i != 0)

                  {

                       if (roamNo.charAt(i) == 'X')

                       {

                            number = number + 40;

                            i--;

                            continue;

                       }

                  }

                  number = number + 50;

             }

             // FIND OUT WHETHER IT IS 'X' OR NOT

             else if (roamNo.charAt(i) == 'X')

             {

                  if (i != 0)

                  {

                       if (roamNo.charAt(i - 1) == 'I')

                       {

                            number = number + 9;

                            i--;

                            continue;

                       }

                  }

                  number = number + 10;

             }

             // FIND OUT WHETHER IT IS 'V' OR NOT

             else if (roamNo.charAt(i) == 'V')

             {

                  if (i != 0)

                  {

                       if (roamNo.charAt(i - 1) == 'I')

                       {

                            number = number + 4;

                            i--;

                            continue;

                       }

                  }

                  number = number + 5;

             }

            else // FIND OUT WHETHER IT IS 'I' OR NOT

             {

                  number = number + 1;

             }

         }// end for loop

         System.out.println("Roman number: " + roamNo + "\nIts Decimal Equivalent: " + number);

    }

}

3 0
3 years ago
Mintzberg's classification of organizational structure categorizes the knowledge-based organization where goods and services dep
sineoko [7]

Answer:

The correct answer to the following question will be Option 3 (Professional bureaucracy).

Explanation:

  • Professional bureaucracy is evidence that uncentralized organizations can be administrative. Their organizational function is reliable, culminating in "preconceived or repetitive actions, in essence, uniform."It's also very complicated, and so the operators who are doing it should be regulated.
  • Mintzberg's organizational framework categorization classifies the information-based organization where services and goods depend as a highly qualified bureaucracy on both the knowledge and expertise of experts.

The other alternatives are not related to the structure of the Mintzberg. So choice 3 is the correct answer.

8 0
3 years ago
Which of the following is an example of synchronous communication?
kirza4 [7]

The answer is D) on Oddessey Ware

4 0
3 years ago
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