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GarryVolchara [31]
3 years ago
11

150 pounds shared into the ratio of 4:1

Mathematics
1 answer:
V125BC [204]3 years ago
4 0

\begin{cases}x+y=150\smallskip\\\dfrac{x}{y}=\dfrac{4}{1}\end{cases}\Leftrightarrow\begin{cases}x+y=150\smallskip\\x=4y\end{cases}\Leftrightarrow\begin{cases}5y=150\smallskip\\x=4y\end{cases}\Leftrightarrow\begin{cases}y=30\smallskip\\x=120\end{cases}

150=120+30

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The diameter of a circle is 23 inches and the circle has two chords of length 14 inches what is the distance from each chord to
Svetradugi [14.3K]

Answer:

9.12 + 9.12 = 18.24 inches

Step-by-step explanation:

Diameter = 23 inches (given)

Radius = 11.5 inches

2 Chords of length = 14 inches ( You didn't specify if the 14 inches is for both chords or for a single cord. I'll assume it's for two cords 14 and 14inches apart.

To clearly solve this, we'll make some mild assumptions.

Let the perpendicular distance of the chords from the center of the circle to represented as " x and y"

Therefore:

x^2 + 7^2 = 11.5 ^ 2

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x^2 = 83.25

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Since the cords have thesame length (Assumed from the way the question was structured, the distance would still be thesame)

y^2 + 7^2 = 11.5 ^ 2

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Therefore, the distance will be :

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6 0
3 years ago
What is the value of k in the equation StartFraction k Over 3 EndFraction minus 5 = 34?
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\huge\text{$k=\boxed{117}$}

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To find the value of k, we need to isolate it on one side of the equation. Add 5 to both sides of the equation, then multiply both sides of the equation by 3.

\displaystyle\begin{aligned}\frac{k}{3}-5+5&=34+5\\\frac{k}{3}&=39\\\frac{k}{3}*3&=39*3\\k&=\boxed{117}\end{aligned}

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Answer:

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Alex73 [517]

Answer:

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Step-by-step explanation:

JQ is 5 times the length of JK

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JK = 42

● JQ = 5 × 42

● JQ = 210

8 0
3 years ago
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