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Rashid [163]
4 years ago
15

What is one fifth of an inch

Mathematics
1 answer:
Brums [2.3K]4 years ago
4 0
The answer would be 0.2 inches! Hope this helps!!
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Which ordered pair in the form (a,b) is a solution of the equation?
kondor19780726 [428]

Answer:

A. (6,0)

Step-by-step explanation:

4a- 5b = 24

Check each point to see if its is true

A. (6,0)

4(6) - 5(0) = 24

24 = 24

true

B. (-5, -2)

4(-5) -5(-2)= 24

-20 +10 = 24

-10 =24

False

C. (0,6)

4(0) -5(6) =24

-30 =24

False

D. (-2, -5)

4(-2) -5(-5)=24

-8+25=24

18=24

False

3 0
3 years ago
Aidan has $65 in his bank account. His brother Michael also has a bank account. They want to calculate the amount of money in bo
stepan [7]

Answer:

C because they won't know unless they know what Michael has

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
WRITE Math How are a common denominator and a common<br> multiple alike and different?
Vesnalui [34]
That are different because that are not!!!!! the same ?
8 0
4 years ago
Read 2 more answers
How to take derivative of absolute value.
zhenek [66]

The absolute value function is defined as

|x| = \begin{cases}x & \text{for }x \ge 0 \\ -x & \text{for }x < 0\end{cases}

If x is strictly positive (x > 0), then |x| = x, and d|x|/dx = dx/dx = 1.

If x is strictly negative (x < 0), then |x| = -x, and d|x|/dx = d(-x)/dx = -1.

But if x = 0, the derivative doesn't exist!

In order for the derivative of a function f(x) to exist at x = c, the limit

\displaystyle \lim_{x\to c}\frac{f(x) - f(c)}{x-c}

must exist. This limit does not exist for f(x) = |x| and c = 0 because the value of the limit depends on which way x approaches 0.

If x approaches 0 from below (so x < 0), we have

\displaystyle \lim_{x\to 0^-}\frac{|x|}x = \lim_{x\to0^-}-\frac xx = -1

whereas if x approaches 0 from above (so x > 0), we have

\displaystyle \lim_{x\to 0^+}\frac{|x|}x = \lim_{x\to0^+}\frac xx = 1

But 1 ≠ -1, so the limit and hence derivative doesn't exist at x = 0.

Putting everything together, you can define the derivative of |x| as

\dfrac{d|x|}{dx} =  \begin{cases}1 & \text{for } x > 0 \\ \text{unde fined} & \text{for }x = 0 \\ -1  & \text{for }x < 0 \end{cases}

6 0
3 years ago
An angle measures 16° more than the measure of its supplementary angle. What is the measure of each angle?
user100 [1]

Answer:

the surface are of a rectangle box of 5cm long, 3cm wide and 4cm wide is 94cm²

3 0
3 years ago
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