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3 years ago

9

!!!ANSWER ASAP 100 POINTS!!! ANSWER BOTH AND TELL ME EXACTLY WHAT GOES IN EACH BOX

1 answer:

Zielflug [23.3K]3 years ago

8 0

Answer:

1. 7¹⁰

2. 9⁸

Step-by-step explanation:

1. 7 = 7¹

Hence, using the rules of indices..... you would add the exponents when numbers that have the same base are multiplied together.

7⁹⁺¹ = 7¹⁰

2. Add exponents

9²⁺⁶ = 9⁸

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I need help!!! Please help ASAP!

zhannawk [14.2K]

180 ≥ 45 + 15x

<u> -45</u> <u>-45 </u>

135 ≥ 15x

9 ≥ x

x ≤ 9

Answer: D

66 < 2x + 28

<u>-28 </u> <u> -28 </u>

38 < 2x

19 < x

x > 19

Answer: C <em>the answer could also be B</em>

11 < 5 + 2x

<u>-5</u> <u>-5 </u>

6 < 2x

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Answer: E <em>the answer could also be A, B, and C</em>

-30 ≥ 6 - 4x

<u> -6</u> <u> -6 </u>

-36 ≥ -4x

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<u> + 4 </u> <u>+ 4 </u>

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Answer: B

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3 years ago

Can 11/154 be simplified

Kryger [21]

Yes, if it exists, and reduce our fraction by dividing both numerator and denominator by it. GCF = 11, and get our simplified answer

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3 years ago

Read 2 more answers

All the square numbers between 20 and 50

Mariana [72]

it is 3 numbers all together and they are 25, 36 and 49.

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2 years ago

Find the absolute maximum and minimum values of f(x,y)=xy−4x in the region bounded by the x-axis and the parabola y=16−x2.

skad [1K]

Answer:

The absolute maximum and minimum is $20\; \text{and} -20.$

Step-by-step explanation:

We first check the critical points on the interior of the domain using the

first derivative test.

$f_x=y-4=0$

$f_y=x=0$

The only solution to this system of equations is the point (0, 4), which lies in the domain.

$f_{xx}=0, \;f_{yy}=0\; \text{and}\; f_{xy}=-1$

$\Rightarrow f_{xx}f_{yy}-f_{xy}=o-1=-1$

$\therefore (0,4)$ is a saddle point.

Boundary points - $(4,0), (-4,0), (0,16)$

Along boundary $y=16-x^2$

$f=x(16-x^2)-4x$

$=16x-x^3-4x$

$\Rightarrow f^'=16-3x^2-4=0$

$\Rightarrow 3x^2=12$

$\Rightarrow x=\pm2,\;\;y=14$

Values of f(x) at these points.

$\begin{array}{}(4,0)=-16\\(-4,0)=16\\(0,16)=0\\(2,14)=20\\(-2,14)=-20\end{array}$

Therefore, the absolute maximum and minimum is $20\; \text{and} -20.$

6 0

3 years ago

If h(x)=(fog)(x) and h(x)=³√x+3, find g(x) if f(x) =³√x+2

ipn [44]

Answer:

$g(x)=x+1$

The problem:

Find $g(x)$ if $h(x)=(f \circ g)(x)$ ,

$h(x)=\sqrt[3]{x+3}$ , and

$f(x)=\sqrt[3]{x+2}$ .

Step-by-step explanation:

$h(x)=(f \circ g)(x)$

$h(x)=f(g(x))$

Replace $x$ in $f(x)=\sqrt[3]{x+2}$ with $g(x)$ since we are asked to find $f(g(x))$ :

$\sqrt[3]{x+3}=\sqrt[3]{g(x)+2}$

$\sqrt[3]{x+1+2}=\sqrt[3]{g(x)+2}$

This implies that $x+1=g(x)$

Let's check:

$(f \circ g)(x)$

$f(g(x))$

$f(x+1)$

$\sqrt[3]{(x+1)+2}$

$\sqrt[3]{x+1+2}$

$\sqrt[3]{x+3}$ which is the required result for $h(x)$ .

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3 years ago