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Molodets [167]
3 years ago
9

!!!ANSWER ASAP 100 POINTS!!! ANSWER BOTH AND TELL ME EXACTLY WHAT GOES IN EACH BOX

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
8 0

Answer:

1. 7¹⁰

2. 9⁸

Step-by-step explanation:

1. 7 = 7¹

Hence, using the rules of indices..... you would add the exponents when numbers that have the same base are multiplied together.

7⁹⁺¹ = 7¹⁰

2. Add exponents

9²⁺⁶ = 9⁸

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I need help!!! Please help ASAP!
zhannawk [14.2K]

180 ≥ 45 + 15x

<u> -45</u>   <u>-45        </u>

135 ≥         15x

  9 ≥  x

   x ≤ 9

Answer: D

66 < 2x + 28

<u>-28 </u>  <u>        -28 </u>

38 <  2x

 19 <  x

  x > 19

Answer: C  <em>the answer could also be B</em>

11 < 5 + 2x

<u>-5</u>  <u>-5         </u>

6 <       2x

3  <  x

x > 3

Answer: E   <em>the answer could also be A, B, and C</em>

-30 ≥ 6 - 4x

<u>  -6</u>   <u> -6      </u>

-36 ≥    -4x

  9 ≤ x

   x ≥ 9

Answer: A

\frac{x}{12} - 4 ≥ 5

<u>       + 4 </u>  <u>+ 4 </u>

\frac{x}{12}    ≥ 9

12(\frac{x}{12}) ≥ 12(9)

 x   ≥ 108

Answer: B

8 0
3 years ago
Can 11/154 be simplified
Kryger [21]

Yes, if it exists, and reduce our fraction by dividing both numerator and denominator by it. GCF = 11, and get our simplified answer

6 0
3 years ago
Read 2 more answers
All the square numbers between 20 and 50
Mariana [72]

it is 3 numbers all together and they are 25, 36 and 49.

4 0
2 years ago
Find the absolute maximum and minimum values of f(x,y)=xy−4x in the region bounded by the x-axis and the parabola y=16−x2.
skad [1K]

Answer:

The absolute maximum and minimum is 20\; \text{and} -20.

Step-by-step explanation:

We first check the critical points on the interior of the domain using the

first derivative test.

f_x=y-4=0

f_y=x=0

The only solution to this system of equations is the point (0, 4), which lies in the domain.

f_{xx}=0, \;f_{yy}=0\; \text{and}\; f_{xy}=-1

\Rightarrow f_{xx}f_{yy}-f_{xy}=o-1=-1

\therefore (0,4) is a saddle point.

Boundary points -  (4,0),  (-4,0), (0,16)

Along boundary  y=16-x^2

   f=x(16-x^2)-4x

=16x-x^3-4x

\Rightarrow f^'=16-3x^2-4=0

\Rightarrow 3x^2=12

\Rightarrow x=\pm2,\;\;y=14

Values of f(x) at these points.

\begin{array}{}(4,0)=-16\\(-4,0)=16\\(0,16)=0\\(2,14)=20\\(-2,14)=-20\end{array}

Therefore, the absolute maximum and minimum is 20\; \text{and} -20.

6 0
3 years ago
If h(x)=(fog)(x) and h(x)=³√x+3, find g(x) if f(x) =³√x+2
ipn [44]

Answer:

g(x)=x+1

The problem:

Find g(x) if h(x)=(f \circ g)(x),

h(x)=\sqrt[3]{x+3}, and

f(x)=\sqrt[3]{x+2}.

Step-by-step explanation:

h(x)=(f \circ g)(x)

h(x)=f(g(x))

Replace x in f(x)=\sqrt[3]{x+2} with g(x) since we are asked to find f(g(x)):

\sqrt[3]{x+3}=\sqrt[3]{g(x)+2}

\sqrt[3]{x+1+2}=\sqrt[3]{g(x)+2}

This implies that x+1=g(x)

Let's check:

(f \circ g)(x)

f(g(x))

f(x+1)

\sqrt[3]{(x+1)+2}

\sqrt[3]{x+1+2}

\sqrt[3]{x+3}  which is the required result for h(x).

6 0
3 years ago
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