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Molodets [167]
4 years ago
9

!!!ANSWER ASAP 100 POINTS!!! ANSWER BOTH AND TELL ME EXACTLY WHAT GOES IN EACH BOX

Mathematics
1 answer:
Zielflug [23.3K]4 years ago
8 0

Answer:

1. 7¹⁰

2. 9⁸

Step-by-step explanation:

1. 7 = 7¹

Hence, using the rules of indices..... you would add the exponents when numbers that have the same base are multiplied together.

7⁹⁺¹ = 7¹⁰

2. Add exponents

9²⁺⁶ = 9⁸

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Gennadij [26K]
Nopeeeeeeeeeeeeeeeeeeee
5 0
3 years ago
Read 2 more answers
A shop advertised a 22% off sale. If a coat originally sold for $255, find the decrease in price and sale price.
Umnica [9.8K]
It would be: 255 - (255 * 22%)
= 255 - (255 * 0.22)
= 255 - 56.1
= 198.9

In short, Decrease in Price is $56.1 & Sale Price is $198.9

Hope this helps!
8 0
3 years ago
Necesito que me ayuden con unas tareas de matematicas de primer grado de secundaria​
Alex_Xolod [135]

Answer: i don't know

Step-by-step explanation:

                               

5 0
3 years ago
In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g
KIM [24]

Answer:

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

All girls from the first group:

20 students, so N = 20

10 girls, so k = 10

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163

All girls from the second group:

20 students, so N = 20

5 girls, so k = 5

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006

All girls from the third group:

20 students, so N = 20

8 girls, so k = 8

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

7 0
3 years ago
What is the surface area of this right rectangular prism?
tiny-mole [99]

Answer:

32 yd^2

Step-by-step explanation:

Ignore rounded approximations (i.e. 2.66, 1.33). For all calculations, use fractions and EXACT values.

This prism has 6 surfaces:

  1. Front: 3 x 2.66 = 8
  2. Back: 3 x 2.66 = 8
  3. Top: 3 x 1.33 = 4
  4. Bottom: 3 x 1.33 = 4
  5. Side: 1.33 x 2.66 = 4
  6. Side: 1.33 x 2.66 = 4

Total SA: 8(2) + 4(4) = <u>32 yd^2</u>

7 0
2 years ago
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