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Andru [333]
2 years ago
11

Find two negative consecutive integers such that the square of the first is five more than the second. Find the integers.

Mathematics
1 answer:
fredd [130]2 years ago
4 0

Answer:

the two consecutive negative integers are -2 and -1.

Step-by-step explanation:

Represent these negative integers by m and n.

Then (because the integers are consecutive) n = m + 1, and m^2 = n + 5.

Substituting m + 1 for n in the second equation, we get:

m^2 = m + 1 + 5, or

m^2 - m - 6 = 0

This factors into (m - 3)(m + 2) = 0.  The only negative root is -2.  

Thus, the two consecutive negative integers are -2 and -1.

Check:  Is the  square of the first five more than the second?

Is (-2)^2 = -1 + 5?  YES

The integers aer -2 and -1.

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7 0
3 years ago
(using tables of x- and y-values).
aev [14]

Answer:

a

Step-by-step explanation:

x² - 3 = 2x ( subtract 2x from both sides )

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the factors are - 3 and + 1 , since

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Nady [450]

Answer:

I believe you are correct

Step-by-step explanation:

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Zinaida [17]

Answer:

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Step-by-step explanation:

If you are using a TI-83 plus or something of that sort then you can follow along

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2nd VARS (Distr)

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