Answer:
V'(5, - 6)
Step-by-step explanation:
V(-5, 6)
For a counterclockwise rotation at 180°about the origin ;
The point (a, b) becomes - - - - > (-a, - b)
Therefore,
If ; V(-5, 6) is rotated 180° counterclockwise about the origin, we have ;
V(-5, 6) - - - - > V'(5, - 6)
65.8 is equivalent to <span> -6+ 4 5 −8.2+ 3 5
</span>
Answer:
Rotation was used to transform the figure.
Step-by-step explanation:
Since only one transformation was used, rotating the pre-image ABC 180° counterclockwise around the origin formed the image DEF.
I hope this helped! :-)
Answer:
Real numbers for both
Step-by-step explanation:
The domain of a function is the set of values that the unknown t can adopt. For this function, t can be any real number as there are no restrictions for the t. Ir can be any positive number, 0, negative numbers, fractions, irrational numbers, whatever number you like.
The range of a function is the values that p(t) adopt when we replace the t value with any number. Here, again, it range is all real numbers. If you want p(t) to be positive it is possible, negative is possible, 0 is possible, and so on. If you like, you can verify it by replacing the numbers you like.
Something to know is that linear polynomial functions ALWAYS have their domains and ranges in real numbers.
