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3 years ago

How do you know to add or subtract when doing polynomials?

Mathematics

1 answer:

grin007 [14]3 years ago

8 0

Answer:

Adding and Subtracting Polynomials. When adding and subtracting polynomials , you can use the distributive property to add or subtract the coefficients of like terms. Use the commutative property to group like terms. (Recall that "like terms" are monomials with the same variables, such as 3 x 2 y and 82 x 2 y .)

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7x-5=8(x*3) what value of x makes this equation true

hram777 [196]

The given equation is:

$\displaystyle 7x-5=8(x+3)$

The first step you need to do is open the parentheses and distribute the 8 to x+3. It will be 8 times x and 3 times x.

$8(x+3)=8 \times x+ 8 \times 3\\\\8 \times x=8x\\8 \times 3=24$

$8(x+3) \rightarrow 8x+24$

Rewrite the equation:

$7x-5=8x+24$

Now you need to move one of the variables to the other side.

If you move 7x to the other side, then:

You can move the variable by doing the opposite of it. Since 7x is positive, you can move it by subtracting 7x, which is negative. Subtract 7x on both sides:

$7x-5-7x=8x+24-7x\\-5=x+24$

Now you need to leave x alone. x is being added to 24, so remove it by subtracting both sides by 24. Remember that when you're subtracting from a negative number, you're actually adding while keeping the negative sign.

$-5-24=x+24-24$

Subtract:

$\bf-29=x$

If you move 8x to the other side, then:

8x is positive, so you can move it by subtracting 8x, which is negative. Subtract 8x on both sides:

$7x-5-8x=8x+24-8x\\-x-5=24$

You need to leave the variable alone, so move -5 to the other side. You can do this by adding 5 to both sides.

$-x-5+5=24+5\\-x=29$

Lastly, x is negative, but you're looking for the value of positive x. Divide both sides by -1 to remove the negative sign.

$\displaystyle \frac{-x}{-1} =\frac{29}{-1}$

Remember that a positive number divided by a negative number is negative. Divide:

$\bf x=-29$

The answer to your question is x = -29.

8 0

3 years ago

Read 2 more answers

Find the limit (enter 'DNE' if the limit does not exist)

vaieri [72.5K]

Answer:

$\lim\limits_{(x,y)\rightarrow(0,0)}\left(\sqrt{-2x^2-6y^2+1}+1\right)=2$

Step-by-step explanation:

We need to first simplify the expression using rationalization(i.e. if a square root term exists in the denominator, then multiply and divide the whole expression by the denominator(but the change the sign of its middle term))

here, we need to find:

$\lim\limits_{(x,y)\rightarrow(0,0)}\left(\dfrac{-2x^2-6y^2}{\sqrt{-2x^2-6y^2+1}-1}\right)$

first we'll rationalize our expression:

$\dfrac{-2x^2-6y^2}{\sqrt{-2x^2-6y^2+1}-1}\left(\dfrac{\sqrt{-2x^2-6y^2+1}+1}{\sqrt{-2x^2-6y^2+1}+1}\right)$

$\dfrac{-(2x^2+6y^2)(\sqrt{-2x^2-6y^2+1}+1)}{(\sqrt{-2x^2-6y^2+1}+1)^2-(1)^2}$

$\dfrac{-(2x^2+6y^2)(\sqrt{-2x^2-6y^2+1}+1)}{-2x^2-6y^2+1-1}$

$\dfrac{-(2x^2+6y^2)(\sqrt{-2x^2-6y^2+1}+1)}{-(2x^2+6y^2)}$

$\sqrt{-2x^2-6y^2+1}+1$

this is our simplified expression, now we can apply our limits:

$\lim\limits_{(x,y)\rightarrow(0,0)}\left(\sqrt{-2x^2-6y^2+1}+1\right)$

$\sqrt{-2(0)^2-6(0)^2+1}+1$

$1+1$

$2$

the limit does exists and it is 2.

5 0

3 years ago

A square has side lengths that measure 8 inches. A rectangle has a length of ten inches and a width of 5 inches. How many more s

Marysya12 [62]

The answer is seven square inches

6 0

3 years ago

The Jacksons went on a 700 mile trip. On the first day they drove 6 and 2/3 hours and on the second day the drove 5 and 3/4 hour

likoan [24]

Answer:

Step-by-step explanation:

Total number of miles is 700.

On the first day, they drove 6 and 2/3 hours. We would convert 6 and 2/3 hours to improper fraction. It becomes 20/3 hours. On the second day, they drove 5 and 3/4 hours. Converting to improper fraction, it becomes 23/4 hours. Total number of hours that they drove during the first two days is the sum of hours driven on the first day and hours driven on the Second day. It becomes

20/3 + 23/4 = (80 + 69)/12

= 149/12 hours

7 0

3 years ago

Help me pleeeeeeeease

Dennis_Churaev [7]

1. Is C 2. Is A 3. Might be D 4. Is B 5. Is D

8 0

3 years ago