If someone answers this correctly I'll give em 100 points
1 answer:
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Answer:
Step-by-step explanation:
This is a polynomial of degree 2, and remember that complex roots always come in pairs; therefore, in a second degree polynomial you can only have 0 real roots and 2 complex roots, or 2 real roots and 0 complex roots. There is no way you can have 1 real root and 1 complex root because, as stated before, complex (non-real) roots always come in pairs; so the only way of having 1 real root is dumping the polynomial of degree 2 (
) by changing the 14 to 0. That way we'll left with 
which only has one real root:
6n+1 = 25
subtract 1 from each side
6n+1-1 = 25-1
6n = 24
divide each side by 6
6n/6 = 24/6
n =4
