Can someone please help me!!

nikitadnepr [17]

Considering the given discrete probability distribution, it is found that the expected share is of 10%.

<h3>What is the mean of a discrete distribution?</h3>

The expected value of a discrete distribution is given by the <u>sum of each outcome multiplied by it's respective probability</u>.

In this problem, the distribution is given by:

P(X = 0.05) = 0.2.

P(X = 0.1) = 0.6.

P(X = 0.15) = 0.2.

Hence the expected value is given by:

E(X) = 0.2 x 0.05 + 0.6 x 0.1 + 0.2 x 0.15 = 0.1 = 10%.

The expected share is of 10%.

More can be learned about the expected value of a discrete distribution at brainly.com/question/24802582

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6 0

2 years ago

Jocelyn is training for a race by running several miles each day. she tracks her progress by recording her average speed in minu

Luden [163]

Finding the regression equation, her average speed on the 9th day should be expected to be of 6.92 minutes per mile.

<h3>How to find the equation of linear regression using a calculator?</h3>

To find the equation, we need to insert the points (x,y) in the calculator.

Researching the problem on the internet, the values of x and y are given as follows:

Values of x: 1, 2, 3, 4, 5, 6.

Values of y: 8.2, 8.1, 7.5, 7.8, 7.4, 7.5.

Hence, using a calculator, the equation for the average minutes per mile after t days is given by:

V(t) = -0.15143t + 8.28

Hence, for the 9th day, t = 9, hence the estimate is:

V(9) = -0.15143(9) + 8.28 = 6.92 minutes per mile.

More can be learned about regression equations at brainly.com/question/25987747

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4 0

2 years ago

20 POINTS TO WHOEVER ANSWERS THIS FIRST

makkiz [27]

D. 12+T
^^^^^^^^^^^^^

3 0

4 years ago

Read 2 more answers

Circle O has diameter FG and chord FH. Calculate the measure of < HFG if GH = 72°

Angelina_Jolie [31]

Given the figure in the attached image.

Circle O has diameter FG and chord FH.

If arc GH is;

$GH=72^{\circ}$

we want to find the measure of angle HFG.

Recall that from circle geometry theorems;

"The angle at the center of a circle is twice the angle at the circumference of the circle."

So;

$\begin{gathered} 2\times m\measuredangle HFG=m\measuredangle GOH \\ m\measuredangle HFG=\frac{1}{2}m\measuredangle GOH \\ m\measuredangle HFG=\frac{1}{2}GH \end{gathered}$

substituting the value of GH;

$undefined$

5 0

2 years ago

ABCD is a rhombus. The diagonals, AC and BD, intersect at the point M. The coordinates of M are (6, -11). The points A and C bot

Zielflug [23.3K]

Answer:

The exact coordinates of the point where the line through B and D intersects the y-axis is $\left ( 0, \ -12\dfrac{5}{7} \right)$

Step-by-step explanation:

For the given question, we have the following parameters;

The shape of the quadrilateral ABCD in the question = A rhombus

The diagonals of the rhombus = AC and BD

The point of intersection of the diagonals, M = (6, -11)

The equation of the line points A and C lie = 2·y + 7·x = 20

A rhombus is an orthodiagonal quadrilateral (The diagonals of a rhombus are perpendicular)

Therefore;

AC ⊥ BD and where the slope of the line with points A and C is 'm', the slope of the line with points B and D is (-1/m)

Rewriting the equation, 2·y + 7·x = 20, in slope and intercept form, we have;

2·y + 7·x = 20

y = (- 7·x + 20)/2 = -7·x/2 + 10

∴ y = -7·x/2 + 10

The slope of the line 'y = -7·x/2 + 10', m = -7/2

∴ The slope of the line having the points B and D is -1/m = -1/(-7/2) = 2/7

The equation of the line having the points B and D in point and slope form, using point (6, -11) is given as follows;

y - (-11) = 2/7 × (x - 6)

y + 11 = 2·x/7 - 12/7

∴ y = 2·x/7 - 12/7 - 11 = 2·x/7 - 89/7 = 2·x/7 - $12\dfrac{5}{7}$

The equation of the line having the points B and D in point is therefore;

y = 2·x/7 - $12\dfrac{5}{7}$

The coordinates of the point where the line having the points B and D intersects the y-axis is the y-intercept, of the equation, y = 2·x/7 - $12\dfrac{5}{7}$ , which is $\left ( 0, \ -12\dfrac{5}{7} \right)$

8 0

3 years ago