Answer:
Eric will catch up with Jan at 3 o-clock.
Idk I really tried sorry if its wrong lol
Answer:
a. answer to a can be found in the attached file
b. Pr[survival] = Pr[good&survive]+Pr[medium&survive]+Pr[low&survive]=
0.24+0.06+0.05 = 0.35
c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its overall probability of survival?
Pr[survival] = Pr[survival|lands] * Pr[lands] = 0.35 * 0.2 = 0.07
Step-by-step explanation:
"A seed randomly blows around a complex habitat. It may land on any of three different soil types: a high-quality soil that gives a 0.8 chance of seed survival, a medium-quality soil that gives a 0.3 chance of survival, and a low-quality soil that gives only a 0.1 chance of survival. These three soil types (high, medium, and low) are present in the habitat in proportions of 30:20:50, respectively. The probability that a seed lands on a particular soil type is proportional to the frequency of that type in the habitat. a. Draw a probability tree to determine the probabilities of survival under all possible circumstances. b. What is the probability of survival of the seed, assuming that it lands"c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its overall probability of survival?
a. Find the probability tree as attached below
b. Pr[survival] = Pr[good&survive]+Pr[medium&survive]+Pr[low&survive]=
0.24+0.06+0.05 = 0.35
c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its overall probability of survival?
Pr[survival] = Pr[survival|lands] * Pr[lands] = 0.35 * 0.2 = 0.07
Answer:
56.5 in
Step-by-step explanation:
What a delightful little problem ! (Partly because I could see
right away how to do it, and had the answer in a few minutes,
after a lot of impressive-looking algebra on my scratch-paper.)
Three consecutive integers are . . . x, x+1, and x+2
The smallest two are . . . x and x+1
Their product is . . . . . x(x+1)
5 times the largest one is . . . 5(x+2)
5 less than that is . . . . . . 5(x+2)-5
Now, the conditions of the problem say that <u>x (x + 1) = 5 (x+2) - 5</u>
THAT's the equation we have to solve, to find 'x' .
Eliminate parentheses: x² + x = 5x + 10 - 5
Combine like terms: x² + x = 5x + 5
Subtract 5x from each side: x² - 4x = 5
Subtract 5 from each side: <u>x² - 4x - 5 = 0</u>
You could solve that by factoring it, or use the quadratic equation.
Factored, it says that (x + 1) (x - 5) = 0
From which <em>x = -1</em>
and <em>x = +5</em>
We only want the positive results, so our three consecutive integers are
5, 6, and 7 .
To answer the question, the smallest one is <em><u>5 </u></em>.
<u>Check</u>:
5 x 6 ? = ? (7 x 5) - 5
30 ? = ? (35) - 5
30 = 30
yay !
I think the best value for x is -9 because 6 x -9 = 54, minus 8 equals -44.
