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kkurt [141]
3 years ago
11

Which quadrilateral does NOT always have two pairs of parallel sides? A. A Square B. A Parallelogram C. A Trapezoid D. A Rhombus

5th grade math
Mathematics
2 answers:
Yuliya22 [10]3 years ago
4 0
D a rhombus because it dosnt always have congruent sides
lilavasa [31]3 years ago
4 0

Answer:d a rhombus because it dosnt always have congruent sides

Step-by-step explanation:

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Can anyone figure this out
sergey [27]

Answer:

I know it.

Step-by-step explanation:

triangles always add up to 180 degrees so add 43 and 32 together and you will get 75 so then you take 75 off 180 and you will get 105

that's your answer

A = 105

7 0
2 years ago
Suppose that the rate of return on stocks is normally dis-tributed with mean of 9% and a standard deviation of 3%. If I pick fiv
alisha [4.7K]

Answer:

The probability that at least two stocks will have a return of more than 12% is 0.1810.

Step-by-step explanation:

Let <em>X</em> = rate of return on stocks.

The random variable <em>X</em> follows a Normal distribution, N (9, 3²).

Compute the probability that a stock has rate of return more than 12% as follows:

P(X\geq 12)=1-P(X

**Use the <em>z</em> table for the probability.

The probability of a stock having rate of return more than 12% is 0.1587.

Now define a random variable <em>Y</em> as the number of stocks that has rate of return more than 12%.

The sample size of stocks selected is, <em>n</em> = 5.

The random variable <em>Y </em>follows a Binomial distribution.

The probability of a Binomial distribution is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0, 1, 2, ...

Compute the value of P (X ≥ 2) as follows:

P (X ≥ 2) = 1 - P (X < 2)

              = 1 - P (X = 0) - P (X = 1)

              =1-{5\choose 0}(0.1587)^{0}(1-0.1587)^{5-0}-{5\choose 1}(0.1587)^{1}(1-0.1587)^{5-1}\\=1-0.4215-0.3975\\=0.1810

Thus, the probability that at least two stocks will have a return of more than 12% is 0.1810.

6 0
3 years ago
Please help with these 3 questions and show all work!
Bas_tet [7]
Question 1:
"Match" the letters
DE are the last two letters of BCDE
The last two letters of OPQR is QR
DE is congruent to QR

Question 2:
Blank 3: Reflexive property (shared side)
Blank 4: SSS congruence of triangles (We have 3 sets of congruent sides)

Question 3:
I'm guessing those two numbers are 7.
Since both are 7, AB and AE are congruent.
We know that all the other sides are congruent because it is given.
We also know that there is a congruent angle in each triangle.
Thus, the two triangles are congruent by SAS or SSS.
(Note: I couldn't prove this without the two "7"s because there is no such thing as SSA congruence)

Have an awesome day! :)

8 0
3 years ago
Which sentence contains a misplaced modifier?
spin [16.1K]
A is the right answer
3 0
3 years ago
What multiplication equals to 108?
Lana71 [14]
12 × 9 = 108

36 × 3 = 108

2 × 54 = 108

As many as possible.
4 0
3 years ago
Read 2 more answers
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