Plz help me out im stuck
2 answers:
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To find a fractional part you can use this basic fraction: 
once you insert those parts, just reduce the fraction
part = 35; whole = 90
once you insert those parts, just reduce the fraction
part = 35; whole = 90
Answer:
81 sheep were there on the farm
Step-by-step explanation:
Consider the provided information.
Let x represents the number of goats.
y represents the number of cows.
z represents the number of sheep.
Therefore, the total number of animals are x+y+z
2/5 of the animals were goats. This can be written as:
There were three times as many sheep than cows.
There were 45 more goats than cows,
Substitute the value of x and z in equation 1.
Hence, there are 27 cows.
Substitute the value of y in
Therefore, there are 72 goats.
Substitute the value of y in
Thus, there are 81 sheep.
Answer:
1120 Eagles
Step-by-step explanation:
If the population of Eagles decreases by 4% percent each year, then in 2030 (which is 15 years later), the population would decrease by (4 × 15)%
that is 60%
This indicates that the population of bald eagles in the year 2030 would be 60% less of what it was in the year 2015.
so we have, × 2800
which gives us 1680
this means that the number of bald eagles in the year 2030 would be 1680 less than the number of bald eagles in the year 2015
hence 2800 - 1680
then the answer is 1120 Bald Eagles