3,552,308,725 is three billion five hundred fifty two million three hundred eight thousand seven hundred twenty five.
Answer:
r < 4
Step-by-step explanation:
r+6<10
r < 4
Answer:

If we compare this value with the 47.3 proposed we have the following error

The computed mean is close to the actual mean because the difference between the means is less than 5%.
Step-by-step explanation:
Assuming the following dataset:
Speed 42-45 46-49 50-53 54-57 58-61
Freq. 21 15 6 4 2
And we are interested in find the mean, since we have grouped data the formula for the mean is given by:

And is useful construct a table like this one:
Speed Freq Midpoint Freq*Midpoint
42-45 21 43.5 913.5
46-49 15 47.5 712.5
50-53 6 51.5 309
54-57 4 55.5 222
58-61 2 59.5 119
Total 48 2276
And the mean is given by:

If we compare this value with the 47.3 proposed we have the following error

The computed mean is close to the actual mean because the difference between the means is less than 5%.
P-5=3s-15 because Pete is 20 and Sam is 10. 20-5= 15 and 3(10)-15 also equals 15. The answer is C.