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4 years ago

When two fractions refer to the same whole and have the same denominators explain why you can compare only the numerators

1 answer:

6 0

The denominators are the same, so it is easier to just compare the numerators, as you already know that the denominators are the same. hope that this helped

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Find the sum of 3.0478 and 4.92 using the correct number of significant digits.

Nat2105 [25]

The sum of 3.0478 and 4.92 is $7.9678$ , which have 5 significant digits.

<u>Step-by-step explanation:</u>

We have , $Number1 = 3.0478$ and $Number2 =4.92$ . The significant digits of a number are digits that includes all digits except:

All leading zeros. For example, "013" has two significant figures: 1 and 3;

Trailing zeros when they are merely placeholders to indicate the scale of the number and ,

Spurious digits introduced, for example, by calculations carried out to greater precision than that of the original data, or measurements reported to a greater precision than the equipment supports.

Here $Number1 = 3.0478$ and with significant digit rules $Number2 = 4.9200$ . Now, Sum of both numbers = $Number1 + Number2$

⇒Sum of both numbers = $3.0478 + 4.9200$

⇒Sum of both numbers = $7.9678$

∴ The sum of 3.0478 and 4.92 is $7.9678$ , which have 5 significant digits.

8 0

3 years ago

given the weekly demand curve of a local wine producer is p= 50-0.1q, and that the total cost function is c= 1500+ 10q, where q

ipn [44]

Answer:

a)the weekly profit as a function of price is $P=-10 p^2 + 600 p - 6500$

b) a bottle of wine be sold at $30 to realise maximum profit

c) the maximum profit that can be made by the producer is $2500

Step-by-step explanation:

The weekly demand curve of a local wine producer is p= 50-0.1q

p = price

q = quantity

Revenue function R =Price \times Quantity

R=(50-0.1q)q

$R=50q-0.1q^2$

Cost function: c= 1500+ 10q

Profit function=R(x)-C(x)

Profit function= $50q-0.1q^2-1500-10q$

Profit function= $40q-0.1q^2-1500$ ----1

We have q = 500 - 10 p using p = 50 − 0.1q

$P=-0.1 (500 - 10 p)^2 + 40 (500 - 10 p)- 1500\\P= -10 p^2 + 600 p - 6500$

General quadratic equation: $ax^2+bx+c=0$

On comparing

a = -0.1 , b = 40 , c = -1500

Maximum Profit is at q = $\frac{-b}{2a}=\frac{-40}{2(-0.1)}=200$

To find price must a bottle of wine be sold to realise maximum profit

p= 50-0.1q

p= 50-0.1(200)=30

Substitute the value of q in profit function(1) get the maximum profit

So, Profit function= $40\left(200\right)-0.1\left(200\right)^{2}-1500=2500$

Hence

a)the weekly profit as a function of price is $P=-10 p^2 + 600 p - 6500$

b) a bottle of wine be sold at $30 to realise maximum profit

c) the maximum profit that can be made by the producer is $2500

8 0

3 years ago

What is the volume of the cylinder shown below?

pav-90 [236]

Answer:

2258 cu. units

Step-by-step explanation:

you take 22/7 multiply by radius squared and multiply that by 5

7 0

3 years ago

Read 2 more answers

a bag contains 20 pink marbles and 12 yellow marbles. you choose a marble at random. what is the probability of selecting a pink

Sati [7]

So the total amount of marbles is: 20+12=32
there are 20 pink marbles
20/32 = 10/16 = 5/8 (simplified)

4 0

3 years ago

If you do this ill give you a bunch of points please!!!!!!!

Zarrin [17]

(59, 76) and (65, 100)

y - y1 = m(x - x1)

y - 100 = (100-76)/(65 - 59)(x - 65)

y - 100 = (24/6)(x - 65)

y - 100 = 4(x - 65)

y - 100 = 4x - 260

y = 4x - 160

x = 90

y = 4x - 160

y = 4(90) - 160

y = 360 - 160

y = 200

200 chirps per minute

y = 120

y = 4x - 160

120 = 4x - 160

280 = 4x

x = 70

70 degrees

5 0

3 years ago