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nekit [7.7K]
3 years ago
6

The variables X, Y, and Z represent polynomials where X = a, Y = 3a – 5, and Z = a^2 + 2. What is X^2Y – Z in simplest form?

Mathematics
2 answers:
klasskru [66]3 years ago
4 0
X=a \\
Y=3a-5 \\
Z=a^2+2 \\ \\
X^2Y-Z=a^2(3a-5)-(a^2+2)=3a^3-5a^2-a^2-2=3a^3-6a^2-2

The answer is b.
Serjik [45]3 years ago
3 0

Answer:  Option 'b' is correct.

Step-by-step explanation:

Since we have given that

X=a\\\\Y=3a-5\\\\Z=a^2+2

We need to calculate :

X^2Y-Z

So, we put the values of X, Y, and Z in the expression, then it becomes,

X^2Y-Z=a^2(3a-5)-(a^2+2)\\\\X^2Y-Z=3a^3-5a^2-a^2-2\\\\X^2Y-Z=3a^3-6a^2-2

Hence, Option 'b' is correct.

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Answer:

F(n)=15(n+1)    [ where n is number of months]

F(12)=195

Step-by-step explanation:

Pool pass cost for first month =$30

Pool pass cost after first month = $15 for each month

The total amount charged by the pool can be expressed as a  function F(n) where n represents the number of months.

F(n)=15(n-1)+30

This can be simplified by using distribution.

F(n)=(15n-15)+30

F(n)=15n-15+30

F(n)=15n+15

Take 15 as greatest common factor.

∴ F(n)=15(n+1)

For n=12

F(12)=15(12+1)

F(12)=15(13)

F(12)=195

∴ Amount charged by pool for 12 months = $195

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Answer:

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