Answer:
The pair (0,3) is not a solution to the equation
Step-by-step explanation:
This can be proved by simply replacing the x and y variables in the equation by the x and y values of the pair, and checking if the equation renders a true statement:
By replacing x and y with their values in the pair (0,3), that is x=0 and y=3, in the equation y = 5 - 2x we get:
3 = 5 - 2 (0)
3 = 5 - 0
3 = 5
which is NOT a true statement.
On the other hand, the other two pairs (2,1) and (1,3) render true statements:
1 = 5 - 2 (2)
1 = 5 - 4
1 = 1
and
3 = 5 - 2 (1)
3 = 5 - 2
3 = 3
The answer is C . cube 2
Explanation:
Using PEMDAS its Parentheses, exponents ,multiple then divide and add , subtract
0 = -5n - 2n
0 = -7n <em>|divide both sides by (-7)</em>
<u>n = 0</u>
Yo sup??
let the number of pencils and pens be 8x and 14x
x=2
therefore the number of pens and pencils are
16 pencils and 28 pens
Hope this helps
<span>x(1^2)-2(1)+4(1^3)=6
x - 2 + 4 = 6
x + 2 = 6
x = 4 </span>
