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3 years ago

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Ahmad wants to paint a rectangular region of a wall with one layer of paint. He has 32 ft of tape to tape around the border of t

he region he paints. He is considering three regions with lengths of 8ft, 9ft, and 10ft.

1 answer:

Sonbull [250]3 years ago

5 0

Answer:

the answer is definitely 63,000

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DUE IN 10 MINUTES. PLEASE HELP. WOULD BE VERY THANKFUL

Andrej [43]

Answer:

1. y = 36°

a = 9.7

2. No.. wire H to P/Q is not a tangent

Step-by-step explanation:

see below

7 0

2 years ago

In a circle with a radius of 3 ft, an arc is intercepted by a central angle of 2π3 radians. What is the length of the arc?

madreJ [45]

The correct question is
<span>In a circle with a radius of 3 ft, an arc is intercepted by a central angle of 2π/3 radians. What is the length of the arc?

we know that
in a circle
</span>2π radians -----------------> lenght of (2*π*r)
2π/3 radians--------------> X
X=[(2π/3)*(2π*r)]/[2π]=(2π/3)*r

the lenght of the arc=(2π/3)*3=2π ft

the answer is 2π ft

5 0

3 years ago

Read 2 more answers

* 20 points * help me please.?????........???!

lorasvet [3.4K]

$y=ax^2+bx+c$

A parabola is open up if a > 0.
The vertex formula: $y=a(x-h)^2+k$
(h; k) - the coordinates of the vertex
$B.\ y=x^2+10x+24=x^2+2x\cdot5+24=x^2+2x\cdot5+5^2-5^2+24=(x+5)^2-1$
Therefore h = -5 < 0
Answer: B. y = x² + 10x + 24.

3 0

3 years ago

3. approximate value of log 3 base 7

xxTIMURxx [149]

Answer:

0.56457

Step-by-step explanation:

log 3 with base 7 = (Log 3)/ (Log 7) = 0.47712125 / 0.845098040014

(Log 3) / (Log 7) = 0.56457

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3 years ago

What are the roots for<br> x^2+47=3<br><br> 2x^2+50=4<br><br> 2x^2+85=7

erastovalidia [21]

$x^2+47=3\ \ \ |-47\\x^2=-44\\if\ x\in\mathbb{R}\ then\ x\in\O\\if\ x\in\mathbb{C}\ then\ x=\sqrt{-44}=i\sqrt{44}=i\sqrt{4\cdot11}=\boxed{2\sqrt{11}i}\\---------------------------\\2x^2+50=4\ \ \ |-50\\2x^2=-46\ \ \ \ |:2\\x^2=-23\\if\ x\in\mathbb{R}\ then\ x\in\O\\if\ x\in\mathbb{C}\ then\ x=\sqrt{-23}=\boxed{\sqrt{23}i}\\---------------------------\\2x^2+85=7\ \ \ |-85\\2x^2=-78\ \ \ \ |:2\\x^2=-39\\if\ x\in\mathbb{R}\ then\ x\in\O\\if\ x\in\mathbb{C}\ then\ x=\sqrt{-39}=\boxed{\sqrt{39}i}$

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3 years ago