Answer:
The number of once is 9.1
The number of hundreds is 8.9
Step-by-step explanation:
Given as :
The total of digits having ones and hundreds = 900
The sum of digits = 18
Let The number of ones digit = O
And The number of hundreds digit = H
So, According to question
H + O = 18 .........1
100 × H + 1 × O = 900 ........2
Solving the equation
( 100 × H - H ) + ( O - O ) = 900 - 18
Or, 99 H + 0 = 882
Or , 99 H = 882
∴ H = 
I.e H = 8.9
Put the value of H in eq 1
So, O = 18 - H
I.e O = 18 - 8.9
∴ O = 9.1
So, number of once = 9.1
number of hundreds = 8.9
Hence The number of once is 9.1 and The number of hundreds is 8.9
Answer
X = 6
9/12 = 0.75
6/8 = 0.75
The letter C, because the pattern is this (I think):
Every two letters it states the vowels (a,e,i,o,u)
Then in between every two letters there starts a pattern of, saying the alphabet in order and saying the alphabet backwards.
In other words they merged these two lines:
A, B, C, D, E...
+
Z, Y, X, W, V...
=
A, Z, B, Y, C, X...etc.
then by adding this pattern of vowels you get:
A, Z, E, B, I, Y, O, (C), (U), (X)...
Answer:
1. (3x - 2)(x + 5).
2. 2(x + 4)(x - 2).
3. (2x - 9)(2x + 9).
Step-by-step explanation:
1. f(x) = 3x^2 +13x -10
Try to factor by the ac method:
3 * -10 = -30
We need 2 numbers whose product is -30 and whose sum is + 13.
They are -2 and +15, so we write:
3x^2 + 15x - 2x - 10 Factor by grouping:
= 3x(x + 5) - 2(x + 5)
= (3x - 2)(x + 5).
2. f(x) = 2x^2+4x-16
= 2(x^2 + 2x - 8)
Now we need 2 numbers whose product is -8 and whose sum is + 2.
They are +4 and -2. So:
= 2(x + 4)(x - 2).
3. 4x^2 - 81 This is the difference of 2 squares so the factors are:
(2x - 9)(2x + 9).
Answer:
Plot 
and 
Step-by-step explanation:
Given:
Solving for the positive part of the equation:
Solving for the negative part of the equation:
