3 years ago

* 20 points * help me please.?????........???!

1 answer:

3 0

$y=ax^2+bx+c$

A parabola is open up if a > 0.
The vertex formula: $y=a(x-h)^2+k$
(h; k) - the coordinates of the vertex
$B.\ y=x^2+10x+24=x^2+2x\cdot5+24=x^2+2x\cdot5+5^2-5^2+24=(x+5)^2-1$
Therefore h = -5 < 0
Answer: B. y = x² + 10x + 24.

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