Answer:
given
hope it helps!
Step-by-step explanation:
(10x^3y^2/5x^-3y^44)
= (10/5)(x^3/x^-3)(y^2/y^44)
= (2)(x^6)(y^-42)
= 2x^6y^-42
(2x^6y^-42)^3
= 8x^6*3y^-42*3
= 8x^18y^-126
The distance covered at time t is listed below:
Distance at 2 sec = d(2) = 64 feet
Distance at 4 sec = d(4) = 256 feet
Distance at 6 sec = d(6) = 576 feet
Distance at 8 sec = d(8) = 1024 feet
We are to find the average rate of change between 2 seconds and 6 seconds. The average rate of change will be:
Therefore, the average rate of distance between 2 seconds and 6 seconds is 128 feet per second. This represents the speed of the object. So the speed of the object between 2 and 6 seconds was 128 feet per second.
You are missing the image
$24.51 because for 1 once it costs $2.85 so you would just multiply that 8.6 to find the answer.