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olya-2409 [2.1K]
2 years ago
13

Answer this correctly I'll give brainalist + 10 points

Mathematics
1 answer:
luda_lava [24]2 years ago
4 0

Answer:

22

Step-by-step explanation:

22.5 is more accurate

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PLZ ANSWER QUICK-MATH TRIG
IRISSAK [1]

Answer:

FG = 9.7ft

Step-by-step explanation:

Find the diagram in the attachment.

The diagram is a right angled triangle since one of its angle is 90°

Using SOH CAH TOA to calculate the length FG which is the hypotenuse.

According to SOH

Sin∠G = Opposite/Hypotenuse

To get the ∠G,

∠F+∠H+∠G = 180°

18°+90°+∠G = 180°

∠G = 180°-108°

∠G = 72°

Sin72° = 9.2/FG

FG = 9.2/sin72°

FG = 9.67feet

FG = 9.7ft (to the nearest tenth of a foot)

7 0
3 years ago
At the movie theatre, child admission is $6.50 and adult admission is $9.70 . On Tuesday, four times as many adult tickets as ch
Rasek [7]
6.5c + 9.7a = 1721.4
a = 4c

6.5c + 9.7(4c) = 1721.4
6.5c + 38.8c = 1721.4
45.3c = 1721.4
c = 1721.4 / 45.3
c = 38...so there were 38 childrens' tickets <==
and 152 adult tickets
4 0
3 years ago
(02.01)Polygon LMNP slides 5 units right and 4 units down on the coordinate plane. If the original measure of angle M was 50 deg
yarga [219]

Answer:

50°

Step-by-step explanation:

Transformation is the movement of one point from its initial location to a final location. If an object is transformed, all its points are transformed. Types of transformation is reflection, dilation, rotation and translation.

If an object is translated, it maintains its shape and size as well as the length of its sides and angles, only the location changes.

If polygon LMNP with ∠M of 50° is translated 5 units right and 4 units down to a new point, M' has the same angle measure. Hence ∠M' = 50°

4 0
3 years ago
Prove the theorem (AB )^T= B^T. A^T
Lisa [10]

Answer:

(AB)^T = B^T.A^T  (Proved)

Step-by-step explanation:

Given  (AB )^T= B^T. A^T;

To prove this expression, we need to apply multiplication law, power law and division law of indices respectively, as shown below.

(AB)^T = B^T.A^T\\\\Start, from \ Right \ hand \ side\\\\B^T.A^T = \frac{B^T.A^T}{A^T}.\frac{B^T.A^T}{B^T} (multiply \ through) \\\\                = \frac{A^{2T}.B^{2T}}{A^T.B^T} \\\\=\frac{(AB)^{2T}}{(AB)^T} \ \ (factor \ out \ the power)\\\\= (AB)^{2T-T}  \ (apply \ division \ law \ of \ indices; \ \frac{x^a}{x^b} = x^{a-b})\\\\= (AB)^T \ (Proved)

3 0
3 years ago
Name two pairs of adjacent angles and two pairs of vertical angles in the figure
insens350 [35]
Adjacent angles :

IGJ and IGH

KGL and LGM

vertical angles :

JGK and HGM

IGJ and MGL


hope this helps

7 0
3 years ago
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