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Amanda [17]
3 years ago
11

Write 7:30 in two ways

Mathematics
2 answers:
Aloiza [94]3 years ago
6 0
Three ways are: 

<u>In Fraction Form:</u>  \frac{7}{30}  
<u>In Ratio its</u>: What you said  7:30

And

In a Percent Form Its:  0.23- %
(I got that from dividing 7 by 30.)

Hope IT helped You. :D
Dovator [93]3 years ago
3 0
7 to 30

\frac{7}{30}
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Find the point(s) of intersection (if any) of the plane and the line. Also, determine whether the line lies in the plane. 2x - 2
s2008m [1.1K]

Answer:

the intersection is the point P=(x,y,z)=(8,9,14) and the line does not lie in the plane

Step-by-step explanation:

from the equation of the line

x - 1/2 = y + (3/2)/-1 = (z + 1) / 2  = t (parameter)

then the parametric equation of the line is

x= 1/2 +t

y =  (3/2) + t

z = (-1) + 2*t

therefore from the equation of the plane

2x - 2y + z = 12

2*(1/2 +t) - 2[(3/2) + t]  + [(-1) + 2*t]  = 12

1+2*t - 3 -2*t -1 + 2*t = 12

-3 + 2*t = 12

t= 15/2

therefore there is only one intersection of the line with the plane ( then the line does not lie in the plane , since there would be infinite intersection points). The intersection is

x= 1/2 +t = 1/2 +15/2 = 8

y =  (3/2) + t = (3/2) + 15/2 = 9

z = (-1) + 2*t =  (-1) + 2*15/2  = 14

thus the intersection point P=(x,y,z)=(8,9,14)

7 0
3 years ago
40% of Oatypop cereal boxes contain a prize. Hannah plans to keep buying cereal until she gets a prize. What is the probability
aleksley [76]

Answer:

(0.6)^{n}+n(0.4)(0.6)^{n-1}+\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}

Step-by-step explanation:

We will use the binomial distribution. Let X be the random variable representing the no. of boxes Hannah buys before betting a prize.

Our success is winning the prize, p =40/100 = 0.4

Then failure q = 1-0.4  = 0.6

Hannah keeps buying cereal boxes until she gets a prize. Then n be no. times she buys the boxes.

P(X ≤ 3) = P(X=0) +P(X=1)+P(X=2)+P(X=3)

             = \binom{n}{0}p^{0}q^{n-0} +  \binom{n}{1}p^{1}q^{n-1}+ \binom{n}{2}p^{2}q^{n-2}+ \binom{n}{3}p^{3}q^{n-3}


             =  q^{n}+npq^{n-1}+\frac{n(n-1)(p)^{2}q^{n-2}}{2}+\frac{n(n-1)(n-2)p^{3}q^{n-3}}{6}

             = (0.6)^{n}+n(0.4)(0.6)^{n-1}+[tex]\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}


7 0
3 years ago
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ohaa [14]
The answer is A. Monthly service fee
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Sarah downloaded two apps which were 7.48 kb total. If one app was 4.78 kb, how big was the other app?
Keith_Richards [23]

Answer:

2.7 kb

Step-by-step explanation:

Total kb = 7.48

Total apps = 2

one app = 4.78

another app = x

> 4.78 + x = 7.48

x = 7.48 – 4.78

= 2.7 kb

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36% is 4.3 million of what number?
harina [27]
The correct answer is 11944444
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3 years ago
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